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2 years ago

28,062 divided by 3

Mathematics

2 answers:

sasho [114]2 years ago

6 0

The answer is 9,354.

Galina-37 [17]2 years ago

3 0

28 062 ÷ 3
9 354
9 354 x 3
28062

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how many 5 letter combinations can be created from the letters in the world “friendly” assume that the order of the letters does

Artyom0805 [142]

Answer:

Number of combinations = 56

Step-by-step explanation:

Points to remember

nCₐ = n!/(r!(n - r)!)

The given word is "FRIENDLY"

F R I E N D L Y is a 8 letter word.

To find the number of combinations

5 letters can be selected from 8 letter = 8C₅

8C₅ = 8!/(8 - 5)!5!

= 8!/3!5!

= (8 * 7 * 6* 5!)/(1 * 2 * 3 * 5!)

= 8 * 7

= 56

5 letter combinations can be created from the letters in the world “friendly = 56

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3 years ago

Which of the following illustrates the truth value of the given statements? January is the first month of the year or December i

Dafna11 [192]

First, the need to determine if the statements are true or false.

1) January is the first month of the year. (This statement is true)
2) December is the last month of the year. (This statement is also true)

With this in mind we can determine that what will illustrate the truth value would be:

T T -> T

In other words, since the first statement is true and the second statement is also true then conjunction of both statements would be true.

5 0

3 years ago

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Solving Equations by Adding or Subtracting Fractions Show all working p- 538 = -1124

svetlana [45]

Answer:

-586

Step-by-step explanation:

Add 538 to both sides

p-538+538=-1124+538=

p=-1124-538

=-586

8 0

1 year ago

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What I the slope of the line? y-3=5(x-2)

Zina [86]

Y-3=5(x-2)
y-3=5x-10
y=5x-13
the slope is 5

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2 years ago

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Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third

asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

$average=\frac{81+87+x}{3}$

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

$80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85$

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

$80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x$

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

$\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87$

This ine $72\leq x} \leq 87$ quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0

2 years ago