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Stells [14]
3 years ago
8

What is the least common multiple of 8, 3, and 12?

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

24

Step-by-step explanation:

cause its just math

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3. Which number has the greatest absolute value?<br> A)|-3|<br> B)|-8|<br> C)|2|<br> D)|5|
Bond [772]

Answer:

B

Step-by-step explanation:

|-8|=8, and all the others are less. hope that helped

7 0
3 years ago
Nth term of 1 8 15 22 29
k0ka [10]
This is an arithmetic sequence because each term is 7 greater than the previous term, so 7 is what is called the common difference...

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=first term, d=common difference, n=term number.

We know a=1 and d=7 so:

a(n)=1+7(n-1)

a(n)=1+7n-7

a(n)=7n-6 

The above is the "rule" for the nth term.
8 0
3 years ago
Read 2 more answers
How much does an ice cream cost with 11 ounces of toppings? If they charge $3.00 for an ice cream, plus 50 cents per ounce of to
arlik [135]

Answer:

$8.50

Step-by-step explanation:

multiply 0.50 by 11 to get 5.5 and then add the 3 dollars from the ice cream to get 8.5 - make sure to change 8.5 to $8.50

5 0
2 years ago
Read 2 more answers
A cleaning product sells for $0.75 a quart. Which equation can be used to solve for the total cost, C , of five gallons of the p
ozzi

Answer: b. C = 5 × ($0.75 × 4)

Step-by-step explanation:

Note that 4 quarts = 1 gallon

Therefore, if a cleaning product sells for $0.75 a quart, the equation can be used to solve for the total cost, C , of five gallons of the product will be:

= 5 × ($0.75 × 4)

= 5 × $3

= $15

8 0
3 years ago
The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p
Juliette [100K]

Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5

7 0
3 years ago
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