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Stells [14]
4 years ago
8

What is the least common multiple of 8, 3, and 12?

Mathematics
1 answer:
bija089 [108]4 years ago
4 0

Answer:

24

Step-by-step explanation:

cause its just math

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What value should be added to the expression to create a perfect square? x^2 - 20x
boyakko [2]
To complete the square:
we take the coefficient ox "x" (which in this problem is -20)
we divide it by 2
square that number
then add it to both sides of the equation

-20 / 2 = -10
-10^2 = 100
then we add 100 to both sides of the equation:
x^2 -20x
x^2 -20x +100 = 100
******************************************************
To get the roots of the equation, we take the square root of both sides:
(x -10) * (x-10) = 10
(x-10) = square root (10)
x-10 = <span> <span> <span> 3.1622776602 </span> </span> </span>
x1 = <span> <span> <span> 13.1622776602 </span>
and don't forget that square root of 10 also equals  </span></span><span><span><span> -3.1622776602 </span> </span> </span>
x2 = 10 -<span> <span> <span> 3.1622776602
x2 = </span></span></span> <span> <span> <span> 6.8377223398 </span> </span> </span>


4 0
3 years ago
What is m∠8 if m∠4 = 50°?
r-ruslan [8.4K]

Answer:

D) 50°. You got parallel lines cut by a traversal, so angles 4 and 8 are congruent because they're corresponding angles.

Step-by-step explanation:

6 0
3 years ago
Which of the following can be added without altering any of the fractions?
Murrr4er [49]
<h3>Answer: Choice A</h3>

Why? Because the denominators are both the same at 2x+8. We can only add or subtract fractions when the denominators are the same. The general rule for adding fractions is

\frac{A}{C}+\frac{B}{C} = \frac{A+B}{C}

We have numerators A and B added together over a common denominator C. If we didn't have a common denominator, then we'd have to do a bit of algebraic manipulation to get both fractions to a common denominator. It doesn't have to be the lowest common denominator (LCD), though it's often more efficient that way.

4 0
3 years ago
(2x² + 4x³) + (-4x² + 6x³ - 2)
klemol [59]
Answer is:

10x - 2x - 2
6 0
1 year ago
Find the area under the standard normal curve between z = −2.57 and z = 1.27. Round your answer to four decimal places, if neces
dexar [7]
P(-2.57 ≤ Z ≤ 1.27) = P(Z ≤ 1.27) - P(Z ≤ -2.57)

P(Z ≤ 1.27) = 0.8980
P(Z ≤ -2.57) = 1 - P(Z ≤ 2.57) = 1 - 0.99488 = 0.00512

P(-2.57 ≤ Z ≤ 1.27) = 0.8980 - 0.00512 = 0.89288
0.8929 (4 d.p.)
4 0
3 years ago
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