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andrew11 [14]
3 years ago
8

A 73kg man weighs himself at the north pole and at the equator. How much difference in weight is there, in Newtons?.

Mathematics
2 answers:
DanielleElmas [232]3 years ago
6 0
The formula to follow to solve this problem is F=GmM/ r2 where G is the gravitational constant, 6.67*10^-11, m is mass of the man, M is the mass of the earth and r is the distance. The distance of the north pole is <span>earth is 6751 km while that at the equator is 6378 km. Mass of the earth is  5.97E24 kg. Substituting, the weight at the north pole is 637.80 N and that at the equator is 714.59 N. The difference is 76.79 N.</span>
g100num [7]3 years ago
4 0

If a man 73kg man weighs himself at the North Pole and at the Equator, the difference in weight in Newtons is 719.37. I am hoping that this answer has satisfied your query about this specific question, thank you and have a nice day.

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