Question

A 73kg man weighs himself at the north pole and at the equator. How much difference in weight is there, in Newtons?.

Answer 1

The formula to follow to solve this problem is F=GmM/ r2 where G is the gravitational constant, 6.67*10^-11, m is mass of the man, M is the mass of the earth and r is the distance. The distance of the north pole is earth is 6751 km while that at the equator is 6378 km. Mass of the earth is  5.97E24 kg. Substituting, the weight at the north pole is 637.80 N and that at the equator is 714.59 N. The difference is 76.79 N.

Answer 2

If a man 73kg man weighs himself at the North Pole and at the Equator, the difference in weight in Newtons is 719.37. I am hoping that this answer has satisfied your query about this specific question, thank you and have a nice day.