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3 years ago

Find the slope of the line. -7 , - 1/7, 7, 7/1

Mathematics

2 answers:

frutty [35]3 years ago

5 0

Slope = (y₂-y₁)/(x₂-x₁)
by making (x₁,y₁) = (-2,2) and (x₂,y₂) = (5,3)
∴The slope = (3-2)/(5 - -2) = 1/7

Slav-nsk [51]3 years ago

5 0

We have that
point A(-2,2)
point B (5,3)

step 1 find the slope m
m=(y2-y1)/(x2-x1)------> m=(3-2)/(5+2)-----> m=1/7

the answer is
the slope m=1/7

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Answer:

For the first one, you get x<7.

For the second one, you get x >_ 11

Step-by-step explanation:

For the first one: -2x - 2 > -16

Step 1. Add 2 to both sides.

-2x - 2 +2 > -16 + 2

-2x > -14

Step 2. Divide both sides by -2 and switch the sign

-2x/-2 > -14/-2

x < 7

For the second one: 2x - 1 >_ 21

Step 1: Add 1 to both sides

2x -1 +1 >_ 21 + 1

2x >_ 22

Step 2: Divide both sides by 2

2x/2 >_ 22/2

x >_ 11

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10 decreased by 5 equals 5

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Between which two integers does the square root of 117 lie

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According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for th

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Here, given :

Sample size, n = 39

Sample mean, $\bar X$ = 3.6

Standard deviation of the sample, s =2

The population mean, $\mu_0 = 3$

The significance level, $\alpha = 0.05$

a). Therefore the hypothesis is :

$H_0 : \mu = 3 \text{ Vs} \ H_a: \mu \neq 3$

b). The test statics is given as :

$t = \frac{\bar X - \mu_0}{\frac{s}{\sqrt n}} \rightarrow t_{n-1}$

$t = \frac{3.6-3}{\frac{2}{\sqrt {39}}}$

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c). The p- value is given by :

$P(t_{d.f}>|t_{stat}|)$

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$=0.0688$

d). The conclusion :

In this case, the p-value is $0.688 > \alpha=0.05$

So, we do not reject $H_0$ .

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