Step-by-step explanation:
440÷100×12
52.8
440-52.8
387.2
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
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Vector d can be represented as :

Vector c can be represented as :

we have to create vector d from vector c
So, let's assume a vector x, such that sum of vector x and vector c equals to vector d




Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
The answer is: 8 red marbles!
This is because the equation can be written out like this
Blue to red - 3:2
Now it is, blue to red - 12:x
We have to think, what is the difference from the first equation to the second. We know the number 3 times 4 = 12, so we would do the same for the red, 2 times 4=8
If this helped, give me brainliest :)