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d1i1m1o1n [39]
3 years ago
8

Slices of pizza are sold for $1.50 each. A pizza has x slices. Buying an entire pizza costs $12

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

8 slice of pizza

Step-by-step explanation:

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A pencil costs $0.45, an eraser costs $0.30, and a pencil sharpener costs $0.30. What is the cost of 3 pencils, 2 erasers, and 1
alexandr1967 [171]

Hi!

We know the prices of one pencil, one eraser and one pencil sharpener, which are $0.45, $0.30 and $0.30, respectively. Given that, we will find the cost of 3 pencils, 2 erasers and 1 pencil sharpener like this:

3 * 0.45 + 2 * 0.30 + 1 * 0.30 = 1.35 + 0.60 + 0.30 = 2.25

The cost of 3 pencils, 2 erasers and 1 pencil sharpener is $2.25.

Hope this helps!

3 0
3 years ago
Please help me I just want sleep and I want it to be atleast on 75% so I can continue tomorrow cause I’m tried and my back alrea
photoshop1234 [79]

Answer:

$4

Step-by-step explanation:

Quick tip about 20% tips.

Move the decimal over 1 place to the left and multiply by 2.

For this equation it would look like this:

18.37 ---> 1.837

(1.837)(2) = 3.674

So, if we rounded to the nearest dollar like the question is asking then we round to $4.

Another way to do this is to multiply 18.37 by .20:

(18.37)(.20) = 3.674

Either way it is $4.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

3 0
3 years ago
A binomial probability experiment is conducted with given parameters. Compute the probability of x successes in the n independen
snow_lady [41]

Answer:

P(X = 4) = 0.1876

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 15, p = 0.2

We want P(X = 4). So

P(X = 4) = C_{15,4}.(0.2)^{4}.(0.8)^{11} = 0.1876

7 0
3 years ago
Please help if been stuck on this problem for forever​
Sedbober [7]

Answer:

the answers are:x1=-4 and x2=5

6 0
3 years ago
Help plz !!!!!!!!!!!!!!!!!!!!!!!
hoa [83]
That ones a hardddd one ill let someone else answer thatttttt
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3 years ago
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