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ivann1987 [24]
3 years ago
12

What is the equation of the graph below

Mathematics
2 answers:
Marina86 [1]3 years ago
8 0

Answer:

Equation would be y =  (x + 3)² - 1.

Step-by-step explanation:

Given : Parabolic graph .

To find : What is the equation of the graph below.

Solution : We have given that parabolic graph .

Vertex :  where the parabola changes direction, is called the "vertex" .

The graph opens upward, so the vertex is the minimum point of the parabola.

Vertex in given graph is ( -3 ,-1)

Vertex form of parabola : y = a(x - h)² + k ,

Where ( h , k) is vertex .

When "a" is positive, the graph of y = a(x - h)² + k opens upward and the vertex is the lowest point on the curve and vice- versa

In given graph h = -3 , k =-1 and a = positive.

Plug the values of h ,k  in vertex form

y =  (x - (-3))² - 1

y =  (x + 3)² - 1

Therefore, Equation would be y =  (x + 3)² - 1.

jeyben [28]3 years ago
7 0

Answer:

the first equation

Step-by-step explanation:


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Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?
mixer [17]

Given:

|u|=10 at an angle of 45°.

|v|=13 at an angle of 150°.

w=u+v

To find:

Magnitude and direction angle of w.

Solution:

We have,

w=u+v

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Now,

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u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071

v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833

v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5

Using these information, we get

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R_y=u_y+v_y=7.071+6.5=13.571

\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})

\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})

\text{Direction angle}=-72.8239

\text{Direction angle}=107.1476

\text{Direction angle}\approx 107.1

Now,

|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}

|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}

|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}

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|w|\approx 14.20236

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Answer:

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Step-by-step explanation:

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