Each colection day: D
Number of tops collected on that day: N
D1=1; N1=2
D2=3; N2=8
1) Linear model
N-N1=m(D-D1)
m=(N2-N1)/(D2-D1)
m=(8-2)/(3-1)
m=(6)/(2)
m=3
N-N1=m(D-D1)
N-2=3(D-1)
N-2=3D-3
N-2+2=3D-3+2
N=3D-1
when D=6:
N=3(6)-1
N=18-1
N=17
<span>What is the number of tops collected on the sixth day based on the linear model?
</span>The number of tops collected on the sixth day based on the linear model is 17.
2) Exponential model
N=a(b)^D
D=D1=1→N=N1=2→2=a(b)^1→2=ab→ab=2 (1)
D=D2=3→N=N2=8→8=a(b)^3→8=a(b)^(1+2)
8=a(b)^1(b)^2→8=ab(b)^2 (2)
Replacing (1) in (2)
(2) 8=2(b)^2
Solving for b:
8/2=2(b)^2/2
4=(b)^2
sqrt(4)=sqrt( b)^2 )
2=b
b=2
Replacing b=2 in (1)
(1) ab=2
a(2)=2
Solving for a:
a(2)/2=2/2
a=1
Then, the exponential model is N=1(2)^D
N=(2)^D
When D=6:
N=(2)^6
N=64
<span>What is the number of tops collected on the sixth day based on the exponential model?
</span><span>The number of tops collected on the sixth day based on the exponential model is 64</span>
Answer: 115
Step-by-step explanation: just did it on edg
3 x -2^(n-1)
To answer this question, first solve the equation 3 x -2^(n-1) for n=1, n=2,
n=3, n=4, and n=5.
Where n=1
3 x -2^(1-1)
3 x -2^0
3 x 1
n1 = 3
Where n=2
3 x -2^(2-1)
3 x -2^1
3 x -2
n2 = -6
Where n=3
3 x -2^(3-1)
3 x -2^2
3 x 4
n3 = 12
Where n=4
3 x -2^(4-1)
3 x -2^3
3 x -8
n4 = -24
Where n=5
3 x -2^(5-1)
3 x -2^4
3 x 16
n5 = 48
The next step is to find the summation by adding n1 + n2 + n3 + n4 + n5.
3 + (-6) + (12) + (-24) + (48) =
3 - 6 + 12 - 24 + 48
= 33
The answer is C. 33
Answer:
The Answer is G
Step-by-step explanation:
it looking for the y in the (x,y) x is domain and y is range
Answer:
(A)
Step-by-step explanation:
1/2=x/6
2x=6
x=3
THerefore, (A)
