Answer:
There might be more to this problem that not included?
Based on the question written, J and Q would be anything that is mathematically supported.
I could a virtually endless combination, that's why I think we may be missing part of the question.
Here are some solutions:
J=11, Q = 6 11-5=6
J=12, Q= 7 12-5=7
J= 7, Q = 2 7-5=2
J = 162, Q = 157 162-5=157
Answer:
1 is correct for d
2 is the is no solution
not sure if I'm right been awhile since i did math so sorry if I'm wrong
Step-by-step explanation:
Let A be attendance, t the temperature and n the number of days. Then,
A
A=k
Where k is a constant of proportionality;
If A=3200, T=88 and n=8, then k,
3200=
3200=11k
k=
Rewriting the equation and replacing the value of k,
A=
When t=92 and n=12
The A=
A=
A= 2231
Let the length = x
2 lengths are 2x.
Then you have 400 - 2x for both widths, so the width is 200 - x.
The are if the rectangle is
y = x(200 - x)
y = 200x - x^2
y = -x^2 + 200x
Take the first derivative ans set equal to zero to find a maximum value.
y' = -2x + 200
-2x + 200 = 0
-2x = -200
x = 100
Since the side of the rectangle is 100, all sides measure 100 ft, and you have a square.
The maximum area is 100 ft * 100 ft = 10,000 ft.
Answer:
120
Step-by-step explanation:
105÷7/8= 120
