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TEA [102]
2 years ago
7

PLS ANSWER QUICK I WILL GIVE BRAINLIEST

Mathematics
1 answer:
NISA [10]2 years ago
8 0

Answer:

B

Step-by-step explanation:

First, we are decreasing the number so it has to be a decrease.

Next, we divide 7/31 and get around 0.23, which also represents 23 percent.

This only shows that 7 is 23 percent of 31, so we need to find the decrease by seeing the difference of 100 and 23.

We get 100 - 23 = 77, and because it is a decrease we get B.

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Please help. Cleary show what the slope and y-intercept are for each problem. An explanation would be nice, but I'm not going to
Romashka-Z-Leto [24]

Answer:

7: Slope: -2/3

8: y-intercept: (0,6)

9: Slope: -2

10: y-intercept: (0,4)

6 0
3 years ago
a wholesaler allows a discount of 25kobo for every 25 naira goods purchased . find the percentage discount allowed.
ZanzabumX [31]

The percentage discount allowed by the wholesaler is 1%

<h3>Percentage</h3>

  • 1 naira = 100 Kobo

25 naira = 25 × 100

= 2500 Kobo

Percentage discount allowed = 25 / 2500 × 100

= 0.01 × 100

= 1%

Therefore, the percentage discount allowed is 1%

Learn more about percentage:

brainly.com/question/843074

#SPJ1

5 0
1 year ago
A polynomial function can be written as (x + 1)(x + 4)(x – 7). What are the x-intercepts of the graph of this function?
attashe74 [19]

Answer:

fourth option

Step-by-step explanation:

Given

f(x) = (x + 1)(x + 4)(x - 7)

To find the x- intercepts let f(x) = 0, that is

(x + 1)(x + 4)(x - 7) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 4 = 0 ⇒ x = - 4

x - 7 = 0 ⇒ x = 7

x- intercepts are (- 1, 0 ), (- 4, 0 ), (7, 0 )

6 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
Follow this link to view Juan's work. Critique Juan's work by justifying correct solutions and by explaining any errors he made
Aleksandr [31]

Answer:

I don't no sorry please bro sorry

4 0
3 years ago
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