A. solve for 1 variable
let's solve for x in 2nd equation
add 2y to both sides
x=2y+4
sub 2y+4 for x in other equation
3(2y+4)+y=5
6y+12+y=5
7y+12=5
minu12 both sides
7y=-7
divide 7
y=-1
sub back
x=2y+4
x=2(-1)+4
x=-2+4
x=2
(2,-1)
B. eliminate
eliminate y's
multiply first equation by 2 and add to first
6x+2y=10
<u>x-2y=4 +</u>
7x+0y=14
7x=14
divide by 7
x=2
sub back
x-2y=4
2-2y=4
minus 2
-2y=2
divide -2
y=-1
(2,-1)
(2,-1) is answer
Answer: 0.038
Step-by-step explanation:
Given: Total games : n= 375
Number of games won by the team that was winning the game at the end of the third quarter. = 300
The proportion (p) of the team that was winning the game at the end of the third quarter: 
Critical z-value for 90% confidence: z* = 1.645
Margin of error =
The margin of error in a 90% confidence interval estimate of p 
Hence, the required margin of error = 0.038
The same line is written in two different forms
Bro bruhhhh bruh bruh ahahahhaah 2092&29 answer is D
A. c + 7 ≤ 3
c ≤ -4
a = 2
b. c - 3 > 1
c > 4
b = 3
c. c - 7 < 3
c < 10
c = 2