Answer:
Yes, the random conditions are met
Step-by-step explanation:
From the question, np^ = 32 and n(1 − p^) = 18.
Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.
Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.
Confidence interval approach is valid if;
1) sample is a simple random sample
2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.
These two conditions are met by the sample described in the question.
So, Yes, the random conditions are met.
The product has decreased by 80 %
<em><u>Solution:</u></em>
The product of the original numbers: xy
One number is decreased by 75 %
Let x be the number decreased by 75 %
new number = x - 75 % of x
Another number is decreased by 20 %
Let y be the number decreased by 20 %
new number = y - 20 % of y
<em><u>Now the product is given as:</u></em>
<em><u>Now we have to find the percent decreased</u></em>
Subtract new product and original product and then divide by original product . Multiply the result by 100 to get percentage
Here negative sign denotes decrease
Thus the product has decreased by 80 %
1yd=3ft...so 39ft=(39/3)=13yds
1mins =60seconds
13/60=0.22yds/secs
Step-by-step explanation:
there are 50 students and 5 prizes (1 + 1 + 3).
so, already in natural language we would say "there is 1 prize for every 10 students".
formally, remember the rule of probability : desired outcomes over total possible outcomes.
this is here
5/50 = 1/10 = 0.1
your can see it also this way :
if there was only 1 prize, each student would have a chance of 1/50 of winning.
now there are 5 prizes, which gives everybody 5 times the chance of winning. which is then 5×1/50 = 5/50 = 0.1
Answer:
24 is the answer
hope this helps
have a good day :)
Step-by-step explanation: