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3 years ago

Use the correct order of operations to solve the problem below

Mathematics

1 answer:

andrew11 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

The order of operations can be remembered with PEMDAS:

Parentheses

Exponents

Multiplication and

Division from left to right

Addition and

Subtraction from left to right

Example:

$12^2-23+(9*3)$

simplify Parentheses:

$12^2-23+(27)\\12^2-23+27$

simplify Exponents:

$144-23+27$

simplify Addition and Subtraction left to right:

$121+27\\148$

Finito.

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What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?

san4es73 [151]

Answer:

a(n)=3+(n-1)2

Step-by-step explanation:

a(n)=3+(n-1)2

arithmetic sequence

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3 years ago

Which is the graph for the equation y=-3x + 4?

Ivahew [28]

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3 years ago

Tell the slope of a line that contains the points (5,-3) and (7,3)

KiRa [710]

(5,-3)(7,3)
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6 0

3 years ago

Read 2 more answers

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago

What is the slope of the line shown below?

Vedmedyk [2.9K]

Answer is A
8-4/4-2 = 4/2 = 2

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3 years ago