Answer:
1/5
Step-by-step explanation:
slope is rise over run
change in y over the change in X
-8 - (-7) = -1
-9 - (-4) = -5
-1/-5 = 1/5
Step-by-step explanation:
![{ - z}^{6} \\ z = - 3](https://tex.z-dn.net/?f=%20%7B%20-%20z%7D%5E%7B6%7D%20%20%5C%5C%20z%20%3D%20%20-%203)
![- {( - 3)}^{6} \\ = - 1 \times ( - 3 \times - 3 \times - 3 \times - 3 \times - 3 \times - 3)](https://tex.z-dn.net/?f=%20%20-%20%20%7B%28%20-%203%29%7D%5E%7B6%7D%20%20%5C%5C%20%20%3D%20%20-%201%20%5Ctimes%20%28%20-%203%20%5Ctimes%20%20-%203%20%5Ctimes%20%20-%203%20%5Ctimes%20%20-%203%20%5Ctimes%20%20-%203%20%5Ctimes%20%20-%203%29)
= -1 × 729
= -729
Answer:
E. There is sufficient evidence that the mean of the pressure required to open a certain valve has increased.
Step-by-step explanation:
Null hypothesis(H0): μ= 8.4 psi
Alternative hypothesis (H1): μ> 8.4 psi
If the test was due with a representative minimum number of observations. And, if the null hypothesis was rejected, then the mean pressure required to open a valve is greater than 8.4 psi. We can conclude that (at a certain level of confidence) there is sufficient evidence that the mean of the pressure required to open a certain valve has increased.
Answer:
56 Cola-flavored gumballs remaining.
Step-by-step explanation:
There are 180 gumballs. Bob purchased 40 gumballs, which leaves 140 gumballs remaining.
There are four flavors. This is the chance (shown as a percentage) of each flavor Bob recieved:
║GR: 4 ⇒ 10%
║CH: 12 ⇒ 30%
║CO: 16 ⇒ 40%
║OR: 8 ⇒ 20%
So, how can we predict the number of Cola flavored gumballs remaining?
[<em>There is a 40% chance of getting a Cola-flavored gumball from the machine. If we find 40% of 140, we can predict that is close to the number of Cola gumballs left in the machine</em>]
║0.40 ⋅ 140 = 56
40% of 140 is 56, so we can predict there are 56 Cola-flavored gumballs remaining.
Answer:
An equation in slope-intercept form for this line is ![y=\frac{5}{2}x-19](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B2%7Dx-19)
Step-by-step explanation:
Slope intercept form : ![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
We are given that A line passes through the point (4, −9) and has a slope of 5/2.
So, ![(x_1,y_1)=(4,-9)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%284%2C-9%29)
![m = \frac{5}{2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B5%7D%7B2%7D)
Substitute the value in the equation :
So,![y-(-9)=\frac{5}{2}(x-4)](https://tex.z-dn.net/?f=y-%28-9%29%3D%5Cfrac%7B5%7D%7B2%7D%28x-4%29)
![y+9=\frac{5}{2}x-10\\y=\frac{5}{2}x-10-9\\y=\frac{5}{2}x-19](https://tex.z-dn.net/?f=y%2B9%3D%5Cfrac%7B5%7D%7B2%7Dx-10%5C%5Cy%3D%5Cfrac%7B5%7D%7B2%7Dx-10-9%5C%5Cy%3D%5Cfrac%7B5%7D%7B2%7Dx-19)
So, an equation in slope-intercept form for this line is ![y=\frac{5}{2}x-19](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B2%7Dx-19)