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rosijanka [135]
3 years ago
13

I really need help please help me with this​

Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

its point g

Step-by-step explanation:

g is lined up with e so then g is in the center

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Let f(x) =x^2+10x+29<br><br><br> What is the minimum value of the function?<br><br><br> ____
Tems11 [23]

Answer:

hello : the minimum value of the function f is 4

Step-by-step explanation:

f(x) = x² + 10x +29

f(x) = x² +10x+25 +4

f(x) = (x+5)² +4.....(standar form)

if : x = -5      f(-5) = 4 is the minimum value of the function f .

5 0
4 years ago
how to find the period, amplitude, and vertical shift of a sinusoidal graph. please explain in the simplest way possible, tyyyy
Kay [80]

Answer:

Step-by-step explanation:

a) period is the length of one cycle  ( one full squiggle ) If you are lucky and the graph is on exact numbers.. at a high point and to the next high point.. then just take that horizontal distance,  that's one period  also if it's not  you could find the period, T,  by using  T = 2pi / k    where k is a number that represents how fast , or how many times the wave cycles in one second or some other amount of time.  

b) Amplitude is a number that goes right before the sinusoid, which is multiplied by it because,  sin , cos,  are at max 1 or at min -1  

c)  vertical shift is what is added , for upwards shift... before or after the                      sinusoid  ie  sin , cos,  ect ect.

does this help?

4 0
3 years ago
3x2 + 6x = 2? ,9x2 + 2 = 10x. what would be the answers
stich3 [128]
<span>9x2 + 2 = 10x= x=2
</span>i dont know the first one

4 0
3 years ago
What is the approximate estimation for 29.942 + 13.433
Nana76 [90]

Answer:

the answer would be it is approximately <u>4</u><u>3</u><u>.</u><u>8</u><u>5</u>

<u>(</u><u>did </u><u>addition</u><u>)</u>

6 0
3 years ago
Read 2 more answers
What is a situation in which you might locate points on a coordinate grid?
ivanzaharov [21]
A situation could be when you have a y=axsquared+bx+c equation. You'd find the X, or vertex, by doing x=-b divided by 2•a. Then you'd plug in x and find y. Now you have a point you can plot. To find another, you can find the y-intercept by plughing in 0 for x and finding another y.
7 0
3 years ago
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