The wireless device a manager most likely have before being offered the upgrade by her supervisor is a PDA. The wireless device the supervisor most likely offering to the manager as an upgrade would be a smartphone. Laptop and computer would prove cumbersome if the manager needs to have her hands free to move about the sales floor.
This is because a smartphone has various software installed in it that makes the work assigned more easier compared to other gadgets. A laptop and computer can perform the same works as well but the feasibility related to portability will be a reason for the choice on smartphones over PDA, laptops and computer in an organization.
To know more about smartphone here
brainly.com/question/14774245
#SPJ4
The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉
<h3>How to calculate width of the confidence interval with normal distribution?</h3>
The width of the confidence interval will be calculated from the formula;
W = 2Z(σ/√n)
where;
z is the z-score at given confidence level
σ is standard deviation
n is sample size
For first sample;
W_i9 = 2Z(σ/√9)
W_i9 = ²/₃Zσ
For second Sample;
W_i81 = 2Z(σ/√81)
W_i81 = ²/₉Zσ
Thus, we will have;
W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)
W_i9/W_i81 = 9
W_i81 = ¹/₉W_i9
Read more about width of confidence interval at; brainly.com/question/15934877
It produces a hydrazone in which the carbon is attached with the nitrogen atom with the means of a double bond.
Probability of getting exactly 1 heads is 0.094.
As a binomial model, there are only two outcomes, the heads & tails
For a coin, the probability of getting heads or tails = 1 /2 = 0.5
Let 'X' be the no of heads obtained
Let :p" be the probability of getting heads
X~Bin (n=6, p = 0.5)
P (X=x) =
P (X=x) =
P (X=x) =
Note that we need to find probability of getting exactly 1 heads. So we will input the figures
P (X=1) =
P (X=1) =
P (X=1) =
P (X=1) = 0.09375
P (X=1) = 0.094
Therefore, the probability of getting exactly 1 heads is 0.094.
