Answer: p=100t
Step-by-step explanation:
I just took the self assessment for JMHS & this was the correct answer
Answer:
the answer to that is 4 hope it help
Answer:
perimeters of the rectangle=p=46.014 metres
Step-by-step explanation:
Given that:
Length (l) = 21 m
Area of rectangle(A) = 42.15 meter-square
Width (w)=?
Required data:
Perimater of Rectangle=p=?
Calculation:
As we know that Area of rectangle=A=l*w
Putting the value we get
42.15 m(square)=(21 m)*w
or w=42.15/21
or w=2.007 m
Now to find perimters of rectangle we know that
p=2(l + w) metres
putting the values
p=2(21+2.007) metres
p=2(23.007) metres
p=46.014 metres
Just plug in -1 for x and u should get ur answer
6(7+5) + 3
Hope this helps :)
To check:
PEMDAS
7+5 is 12
6(12) + 3
72 + 3
75
