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3 years ago

Exploring Slopes of Parallel and Perpendicular Lines - Item 32539

Mathematics

1 answer:

bekas [8.4K]3 years ago

6 0

What’s the picture of problem

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Pretty please help me

Cerrena [4.2K]

Answer:

Step-by-step explanation:

find there common denominator which is 40

multiply 3 by 8 and 7 by 5 to get 24 and 35

35-24=11

11/40

18-7=11

11 11/40

8 0

3 years ago

Two sisters have decided to watch all the episodes of a popular TV show on DVD. Eva has already watched 9 episodes and will cont

sergejj [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

CAN SOMEONE HELP ME WITH THIS!!! IT IS TIMED

skelet666 [1.2K]

Answer: 2

Step-by-step explanation: Because 2 makes the denominator 0, which makes the entire thing undefined

6 0

3 years ago

How do you do this problem?

Vadim26 [7]

Answer:

Your answer is absolutely correct

Step-by-step explanation:

The work would be as follows:

$\int _0^{\sqrt{\pi }}4x^3\cos \left(x^2\right)dx,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> 4\cdot \int _0^{\sqrt{\pi }}x^3\cos \left(x^2\right)dx\\\\\mathrm{Apply\:u-substitution:}\:u=x^2\\=> 4\cdot \int _0^{\pi }\frac{u\cos \left(u\right)}{2}du\\\\\mathrm{Apply\:Integration\:By\:Parts:}\:u=u,\:v'=\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\int \sin \left(u\right)du\right]^{\pi }_0\\\\$

$\int \sin \left(u\right)du=-\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0\\\\\mathrm{Simplify\:}4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0:\quad 2\left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0\\\\\mathrm{Compute\:the\:boundaries}:\quad \left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0=-2\\=> 2(-2) = - 4$

Hence proved that your solution is accurate.

3 0

4 years ago

Read 2 more answers

3x(12-8)x2)+(11-9)x3)

andriy [413]

3x(12-8)x2)+(11-9)x3) = 14x3 the 3 is squwared tho

4 0

4 years ago