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Alex17521 [72]
4 years ago
14

Christian can clean the room and 20 minutes by himself and Bob can clean the room and 30 minutes by himself how long would it ta

ke to clean the room if they work together
Mathematics
1 answer:
Vsevolod [243]4 years ago
6 0

Answer:

it would take 10 minutes if they worked together

Step-by-step explanation:

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Cerrena [4.2K]
You reduce then evaluate the power. which would be 15-(-6+2+9)÷3-27. then you calculate and then work out the denominator and then divide. I got 13 2/3
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4 years ago
A.S.A.P PLEASE HELP
Monica [59]
To solve this problem yu must apply the proccedure shown below:

 1. You have that the <span>focus of the parabola is located at (0,–2) and the directrix is represented by y=2. Therefore, you have:
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 √(x0-0)²+(y0-(-2))²=|y-2|

 2. By simplifying and clearing x², you obtain:

 (√x0²+(y0+2)²)²=(y0-2)²
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3 years ago
Ax+by=c<br> What is the answer to this?
Nitella [24]

a= -by+c/x

hope it helps

4 0
3 years ago
Read 2 more answers
If two fair dice are tossed, what is the smallest number of throws, n, for which the probability of getting at least one double
amid [387]

This is a rather famous probability problem.

The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice.  There are 36 ways in which dice rols can appear and only one is a twelve.  So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial.  So for your first roll the odds that you WON'T get a 12 is .97222222.

For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.

When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.  

For the 25th roll, we calculate (.97222222)^25 which equals  0.494468.  For the first time we have reached a probability which is lower than 50 per cent.  That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.

To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.

Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page).  An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws.  (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)

Please go that page and it has a link to the Fat the Butch story.


3 0
4 years ago
Show the next 2 term 5. 4,2,0,-2,-4
ICE Princess25 [194]

4,2,0,-2,-4

Minus by 2 for each number

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2-2= 0

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7 0
3 years ago
Read 2 more answers
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