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oksian1 [2.3K]
3 years ago
12

A water tank is a rectangular prism that is 11 meters long 9 meters wide and 6 meters high a solid metal box in 4 meters long 3

meters wide and five meters high is sitting inside the tank what is the volume of the water in the tank
Mathematics
1 answer:
baherus [9]3 years ago
5 0
<h2>A water tank is a rectangular prism that is 11 meters long, 9 meters wide, and 6 meters high. </h2><h2>A solid metal box 4 meters long, 3 meters wide, and 5 meters high is sitting inside the tank. </h2><h2>The tank is filled with water. </h2><h2> </h2><h2>  </h2><h2>What is the volume of the water in the tank? : </h2><h2>Subtract the vol of the box from the volume of the tank </h2><h2>w = (11*9*6) - (4*3*5)</h2>
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Assume that power surges occur as a Poisson process with rate 3 per hour. These events cause damage to a computer, thus a specia
lidiya [134]

Answer:

a) 0.30327

b) 0.07582

Step-by-step explanation:

This is a Poisson distribution problem

Poisson distribution probability function is given as

P(X = x) = (e^-λ)(λˣ)/x!

where λ = mean = 3 power surges per hour

x = variable whose probability is required

a) If a single disturbance in 10 minutes will crash the computer, what is the probability of the computer crashing, that is probability of a single disturbance (power surge) in 10 minutes?

λ = 3 disturbances per hour = 1 disturbance per 20 minutes = 0.5 disturbance per 10 minutes.

P(X = x) = (e^-λ)(λˣ)/x!

λ = 0.5 disturbance per 10 minutes

x = 1 disturbance per 10 minutes

P(X = 1) = (e^-0.5)(0.5¹)/1! = (e⁻⁰•⁵)(0.5)/1!

= 0.30327

b) If two disturbances in 10 minutes will crash the computer, what is the probability of the computer crashing, that is probability of two disturbances (power surges) in 10 minutes?

λ = 3 disturbances per hour = 1 disturbance per 20 minutes = 0.5 disturbance per 10 minutes.

P(X = x) = (e^-λ)(λˣ)/x!

λ = 0.5 disturbance per 10 minutes

x = 2 disturbance per 10 minutes

P(X = 2) = (e^-0.5)(0.5²)/2! = (e⁻⁰•⁵)(0.25)/2!

= 0.07582

Hope this Helps!!!

3 0
3 years ago
Determine the​ value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1s
Leni [432]

Answer: h = 9

Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.

The matrix given is:

\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]

Transform this matrix in a row-echelon form:

\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]   R_{2} = 3R_{2}+R_{1} \left[\begin{array}{ccc}-15&21&h\\0&0&-9+h\end{array}\right]

For this row-echelon form to have solutions:

-9 + h = 0

h = 9

For this system to be consistent: h = 9.

3 0
3 years ago
during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0
3 years ago
Ella grew 3 over 4 of an inch last year. Ben grew 2 over 3 of an inch last year. How much more did Ella grow than Ben last year?
IrinaK [193]

Answer:

Ella grew \frac{1}{12} of an inch more

Step-by-step explanation:

For this problem, you want to subtract Ben's growth from Ella's.

This expression would be \frac{3}{4}-\frac{2}{3}.

To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).

In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by \frac{3}{3} and the second by \frac{4}{4}.

This makes the expression \frac{9}{12}-\frac{8}{12}, which equals \frac{1}{12}.

**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!

7 0
3 years ago
Use this graph to answer the questions below:
stepladder [879]

the x axis and the yaxis

3 0
3 years ago
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