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ddd [48]
3 years ago
15

What is 19xY-X please answer I’m studying for a test

Mathematics
2 answers:
bazaltina [42]3 years ago
4 0

Answer:

is there want other specifics? otherwise I can't do anything except say that it is an incomplete question, it's not even an equation or able to be simplified.

devlian [24]3 years ago
3 0

Simplifying

19xy(x + y) = 0

(x * 19xy + y * 19xy) = 0

Reorder the terms:

(19xy2 + 19x2y) = 0

(19xy2 + 19x2y) = 0

Solving

19xy2 + 19x2y = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '19xy'.

19xy(y + x) = 0

Ignore the factor 19.

Subproblem 1

Set the factor 'xy' equal to zero and attempt to solve:

Simplifying

xy = 0

Solving

xy = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying

xy = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(y + x)' equal to zero and attempt to solve:

Simplifying

y + x = 0

Reorder the terms:

x + y = 0

Solving

x + y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1y' to each side of the equation.

x + y + -1y = 0 + -1y

Combine like terms: y + -1y = 0

x + 0 = 0 + -1y

x = 0 + -1y

Remove the zero:

x = -1y

Simplifying

x = -1y

Solution

x = {-1y}

Answer:

Step-by-step explanation:

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Answer:

1/7

Step-by-step explanation:

Since we do not know the number let us use the alphabet A to represent the unknown number

A × 1/3= 1/21

A/3= 1/21

Cross multiply both sides

A×21= 3×1

21A= 3

Divide both sides by the coefficient of A which is 21

21A/21=3/21

A=1/7

Hence the unknown number is 1/7

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Evaluate, when x=2 y=-5 and z=3
gregori [183]

Answer:

-139

Step-by-step explanation:

Evaluate 1/4 (4 x^3 - 2 y - 2 z^3) y^2 - 16 x^2 where x = 2, y = -5 and z = 3:

(4 x^3 - 2 y - 2 z^3)/4 y^2 - 16 x^2 = (4×2^3 - -5×2 - 2×3^3)/4×(-5)^2 - 16×2^2

(4×2^3 - 2 (-5) - 2×3^3)/4×(-5)^2 = ((4×2^3 - 2 (-5) - 2×3^3) (-5)^2)/4:

((4×2^3 - 2 (-5) - 2×3^3) (-5)^2)/4 - 16×2^2

(-5)^2 = 25:

((4×2^3 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

2^3 = 2×2^2:

((4×2×2^2 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

2^2 = 4:

((4×2×4 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

2×4 = 8:

((4×8 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

3^3 = 3×3^2:

((4×8 - 2 (-5) - 23×3^2) 25)/4 - 16×2^2

3^2 = 9:

((4×8 - 2 (-5) - 2×3×9) 25)/4 - 16×2^2

3×9 = 27:

((4×8 - 2 (-5) - 227) 25)/4 - 16×2^2

4×8 = 32:

((32 - 2 (-5) - 2×27) 25)/4 - 16×2^2

-2 (-5) = 10:

((32 + 10 - 2×27) 25)/4 - 16×2^2

-2×27 = -54:

((32 + 10 + -54) 25)/4 - 16×2^2

| 3 | 2

+ | 1 | 0

| 4 | 2:

(42 - 54 25)/4 - 16×2^2

42 - 54 = -(54 - 42):

(-(54 - 42) 25)/4 - 16×2^2

| 5 | 4

- | 4 | 2

| 1 | 2:

(-12×25)/4 - 16×2^2

(-12)/4 = (4 (-3))/4 = -3:

-3×25 - 16×2^2

2^2 = 4:

-3×25 - 164

-3×25 = -75:

-75 - 16×4

-16×4 = -64:

-64 - 75

-75 - 64 = -(75 + 64):

-(75 + 64)

| 7 | 5

+ | 6 | 4

1 | 3 | 9:

Answer:  -139

8 0
3 years ago
A rectangle has an area of 102cm2. The length of the rectangle is 17 cm. What is the perimeter of the rectangle
tatuchka [14]

Answer:

36

Step-by-step explanation:

To find the with divide 102 by 17, we get 6. Then add 6+6+17+17 because we know this is a rectangle and it has 2 with sides and 2 length sides. We get the answer of 36.

6 0
4 years ago
Complete the following ratio table
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