To obtain the probability of obtaining heads at least 3 times out of 5 times we recall that in her simulation <span>she
assigned odd digits to represent heads and even digits to represent
tails. Thus, we count the simulated numbers to see in how many numbers
do we have 3 or more odd digits.
Below, the simulated numbers with 3 or more odd digits are bolded.
</span> <span>32766 53855 34591 27732
47406 31022 25144 72662
03087 35521 26658 81704
56212 72345 44019 <span>65311
</span>
We have 6 simulated numbers having 3 or more odd digits.
Therefore, </span><span>P("heads" at least 3 out of 5 times) = 6 / 16 = 3 / 8.</span>
Answer:
x=-32/11
Step-by-step explanation:
Let's solve your equation step-by-step.
1/(x+3)=11
(1/n=reciprocal of n)
Step 1: Multiply both sides by x+3.
1=11x+33
11x+33=1(Flip the equation)
11x+33−33=1−33(Subtract 33 from both sides)
11x=−32
11x/11=−32/11
(Divide both sides by 11)
x=−32/11
Check answers. (Plug them in to make sure they work.)
x=−32/11
(Works in original equation)
Answer:
y = -3x + 4
Step-by-step explanation:
I graphed the equation and the point given on the graph below. The other line is the equation that is parallel.
If this answer is correct, please make me Brainliest!
Answer:
The Answer To This Question
is 490.
Step-by-step explanation:
I already answered it.
But seeing as no one else will. Please forgive me
Sorry dude i don’t know this one
