Integers are a subset of irrational numbers.

Mathematics

2 answers:

Paraphin [41]3 years ago

5 0

Answer:

yeah

Step-by-step explanation:

The natural numbers, whole numbers, and integers are all subsets of rational numbers. In other words, an irrational number is a number that can not be written as one integer over another. It is a non-repeating, non-terminating decimal.

Ivan3 years ago

4 0

Answer:

No irrationals are integers. Irrational numbers are by definition *not rational*, and all integers can represented as the rational

You might be interested in

Help please!!! can you show me how to do this??

IrinaK [193]

$\frac{3x - 2}{x^{2} - 2x - 3} - \frac{1}{x - 3} = \frac{3x -2}{(x + 1)(x - 3)} - \frac{1}{x - 3} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{1(x + 1)}{(x + 1)(x - 3)} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{x + 1}{(x + 1)(x - 3)} = \frac{2x - 3}{(x + 1)(x - 3)}$