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White raven [17]
3 years ago
15

Integers are a subset of irrational numbers.

Mathematics
2 answers:
Paraphin [41]3 years ago
5 0

Answer:

yeah

Step-by-step explanation:

The natural numbers, whole numbers, and integers are all subsets of rational numbers. In other words, an irrational number is a number that can not be written as one integer over another. It is a non-repeating, non-terminating decimal.

Ivan3 years ago
4 0

Answer:

No irrationals are integers. Irrational numbers are by definition *not rational*, and all integers can represented as the rational

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The equation y =
-Dominant- [34]

Answer:

The  constant of proportionality k = 12

Hence, option A is true.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get

y ∝ x

y = kx

Where 'k' is called the constant of proportionality.

In our case,

The given equation is

y = 12x

comparing with the equation y = kx, we can say

k = 12 which is the constant of proportionality.

Therefore, we conclude that:

The  constant of proportionality k = 12

Hence, option A is true.

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6 0
2 years ago
Use the Binomial Theorem to expand each binomial (5x-4y)^3
jek_recluse [69]
You should know that:

(a+b)(a+b)(a+b)

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-----------------

If a=5x and b=-4y

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5 0
4 years ago
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matrenka [14]
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3 years ago
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