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2 years ago

Confused on how to set the problem up.

Mathematics

1 answer:

MArishka [77]2 years ago

3 0

Answer: idk but here's some advice re read the question if it says many your gonna add if it say how much then your subtracting and if it says something else then your multiplying or dividing so you have to do 5x133=665 so then that should be your answer

Step-by-step explanation:

Well imma have to keep spamming my question bc no one is even answering it :c

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Hidden cost of being a teacher?

Natali5045456 [20]

Answer:

they have to pay for school supplies

Step-by-step explanation:

7 0

2 years ago

Theo drove 236 miles in 4 hours. Lex drove 195 miles in 3 hours. At those rates, could either man drive 116 miles in 2 hours? Sh

motikmotik

Answer:

No.

Step-by-step explanation:

236÷4=59

195÷3=65

To check if either of them drove 116 miles in 2 hours, I would multiply the sum of the division problems by 2(for 2 hours).

59 x 2 = 118

65 x 2 = 130

None of them equals 116, meaning neither of them drove 116 miles in 2 hours.

Hope I helped you! Have a great day! :)

6 0

2 years ago

35 hundreds = 5 tens times 7 tens is it true or false

Strike441 [17]

True
if you add an imaginary 0 to the numbers since its in the tenths place you would get 3,500
5(0) x 7(0) = 3,500

3 0

3 years ago

Find the length of the leg a of a right triangle with leg length b = 21.5 inches and the hypotenuse c = 31.9 inches. Use a calcu

mylen [45]

The length of the leg a of the right triangle is obtained by applying the Pythagorean theorem which is given as:

$\text{opposite}^2+adjacent^2=hypothenus^2$

Thus, we have that:

$a^2+b^2=c^2$

Given that b = 21.5 inches and c = 31.9 inches, we now have:

$a^2+(21.5)^2=(31.9^2)$ $a^2+462.25=1017.61$ $a^2=1017.61-462.25$ $a^2=555.36$ $\begin{gathered} a=\sqrt[]{555.36}=23.57 \\ \Rightarrow a=23.6\text{ inches (to one decimal place)} \end{gathered}$

Therefore, the length of the leg a of the right triangle is 23.6 inches

4 0

1 year ago

Select the equation that is the inverse of the given function f(x)=x-3/5

vampirchik [111]

$f(x)=\dfrac{x-3}{5}\to y=\dfrac{x-3}{5}\\\\\text{Interchange the y and the x}\\\\x=\dfrac{y-3}{5}\\\\\text{Solve for y}\\\\\dfrac{y-3}{5}=x\qquad|\cdot5\\\\y-3=5x\qquad|+3\\\\y=5x+3\\\\Answer:\ B.\ f^{-1}(x)=5x+3$

7 0

3 years ago

Read 2 more answers