Answer:
I think youranswer will be 67.5
Step-by-step explanation:
Answer:
![\frac{3}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B7%7D)
Step-by-step explanation:
Start by finding how many integers there are from 10-30...
30-10+1=20+1=21
Note we have to add 1 since it is inclusive.
Now, let's find how many multiples of 4 or 5 there are from 10-30...
4*3=12
4*4=16
4*5=20
4*6=24
4*7=28
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5+5-1=9
Note we have to subtract 1 since 20 is counted twice.
The probability would be...
![\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}](https://tex.z-dn.net/?f=%5Cfrac%7BMultiples%5C%20of%5C%20four%5C%20and%5C%20five%5C%20from%5C%2010-30%7D%7BAmount%5C%20of%5C%20integers%5C%20between%5C%2010-30%7D%3D%5Cfrac%7B9%7D%7B21%7D%3D%5Cfrac%7B3%7D%7B7%7D)
Step-by-step explanation: use a histograph
Answer:
No, -1/3 is not a solution
Step-by-step explanation:
See if it is a solution by plugging in -1/3 as v and seeing if the equation is correct:
9v - 2 = 3v
9(-1/3) - 2 = 3(-1/3)
-3 - 2 = -1
-5 = -1
-5
-1
So, since the equation is incorrect, -1/3 is not a solution.
Let the number be x
15% = 90
1% = 6
100% = 6 x 100 = 600