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inna [77]
3 years ago
15

Megan says she never needs to look at the Transport Layer when she is searching for what went wrong with the network she support

s. Is Megan right or wrong, and why? Right, because the Transport Layer is software, and network engineers do not need to focus on software. Right, because the Transport Layer usually does not go wrong in a way that involves a network engineer. Wrong, because if data are coming through garbled, it is a Transport Layer problem. Wrong, because transporting information is what a network does, and the Transport Layer is at the heart of that layer.
Computers and Technology
2 answers:
alisha [4.7K]3 years ago
8 0

Answer:

Right, because the Transport Layer usually does not go wrong in a way that involves a network engineer.

Explanation:

The transport layer is the fourth layer in the OSI networking model. It encapsulates the data with a port number to identify the application port address and split them to segments. It's protocols helps to transport packets to destination devices. Two protocols in the transport layer are the TCP and UDP protocols.

TCP is connection oriented while UDP does not establish a connection. Protocol functions are determined and a network engineer can only analyse it's processes.

lara31 [8.8K]3 years ago
3 0

I'd say D: Wrong, because transporting information is what a network does, and the Transport Layer is at the heart of that layer.

Transport layer is truly at the heart of the OSI model. Its main function is to transfer application data from the source to destination. This layer provides a reliable end-to-end communication service and transfers data for the user layers above it, as well as shielding the rest of the layers below from details like message error and flow control functions. If packets get destroyed or lost during transmission, it is in the best interest of Megan to check the transport layer. Transport layer ensures that whenever something like this happens, packets must be re-transmitted.

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Write the method makeNames that creates and returns a String array of new names based on the method’s two parameter arrays, arra
Gwar [14]

Answer:

  1. import java.util.Arrays;
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        String [] first = {"David", "Mike", "Katie", "Lucy"};
  5.        String [] middle = {"A", "B", "C", "D"};
  6.        String [] names = makeNames(first, middle);
  7.        System.out.println(Arrays.toString(names));
  8.    }
  9.    public static String [] makeNames(String [] array1, String [] array2){
  10.           if(array1.length == 0){
  11.               return array1;
  12.           }
  13.           if(array2.length == 0){
  14.               return array2;
  15.           }
  16.           String [] newNames = new String[array1.length];
  17.           for(int i=0; i < array1.length; i++){
  18.               newNames[i] = array1[i] + " " + array2[i];
  19.           }
  20.           return newNames;
  21.    }
  22. }

Explanation:

The solution code is written in Java.

Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).

In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]

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Answer:

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Explanation:

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Explanation:

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