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Andreas93 [3]
3 years ago
14

When constructing a function what is the slope-intercept form we use? Identify each part.

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

y=mx+b

Step-by-step explanation:

Ray Of Light [21]3 years ago
6 0

Answer:

y=mx+b I think sorry if not

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What is mean of 32 48 22
pentagon [3]

Answer:

34

Step-by-step explanation:

32+48+22=102

102/3=34

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4 years ago
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Use the distributive property to simplify the expression below:
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4x + 2x + 2
= 6x + 2

So the answer is B
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In Bobby’s school, math grades for the year are calculated from assignments, tests and a final exam. Assignments count 30%, test
jarptica [38.1K]

Answer:

A) Bobby's overall grade is 70.4%

Step-by-step explanation:

To solve this problem we must calculate the percentages each grade represents from the overall grade. Therefore:

assignment = 85*30% = 85*30/100 = 25.5%

tests = 72*20% = 72*20/100 = 14.4%

exam = 61*50% = 61*50/100 = 30.5%

total = assignment + tests  + exam

total = 25.5 + 14.4 + 30.5 = 70.4

Bobby's overall grade is 70.4%. Therefore the correct answer is A).

7 0
3 years ago
I need these correct answers nowww
faust18 [17]

Answer:

1 - 3/14

2 - 10 5/8

3 - 3/8

4 - 12 1/4

Step-by-step explanation:

numbers 1 and 3 are simple, just multiply the numerators and denominators together.

Numbers 2 and 4, you convert the mixed number to an improper fraction and multiply. Don't forget to switch the answer back to a mixed number if needed!

3 0
3 years ago
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A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

8 0
3 years ago
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