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gavmur [86]
3 years ago
13

Tell whether the triangle with the given side lengths is a right triangle. 10in., 24in., 26in.

Mathematics
1 answer:
ra1l [238]3 years ago
4 0
Answer- Yes it is a right triangle.
You can use the Pythagorean Theorem.
( a^2 + b^ = c^2 ) and replace a with 10, b with 24, and c with 26 and the equation will be balanced on both sides.

(10^2 + 24^2 = 26^2)
(100 + 576 = 676 )
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Please help me, i dont have graph paper, and im not sure about number 1
qwelly [4]

Answer:

from the values you get

*make a dotted line to intersect the line (do this for both the highest value and lowest value)

* subtract the lowest value from the lowest value

that will be the slop for yaxis

3 0
3 years ago
Read 2 more answers
Can someone please help with this? I'll give brainliest. I don't understand this... or the explanation it gives... the page befo
tresset_1 [31]

Step-by-step explanation:

Hello!
I'd love to help you learn.
I see the formula attached is 4*(\frac{1}{2})^{x} =-2^{x}-1\\

This problem is explaining you to graph, since algebraically it's a little more harder to try and find the solution.

Since they're both equal to each other, we can assign a variable like y, so we can make them into two individual lines.

You can use your scientific calculator to graph lines like this, or otherwise there are online sources (Desmos helps alot!) which can graph two equations as so.

Now that we have the corresponding system of equations, we can graph both.

y=4*(\frac{1}{2})^x\\ y=-2^x-1
Let's graph them on Desmos on the same plane. The answers are attached. Red is the first equation, blue is the second.

What determines the solutions of a system of equations?

-No solution: the two lines will never intersect/does not intersect ever, which means that there are no set point where it satisfies both equations.

-One solution: the two lines intersect once and only once, meaning that there is that one set point where the x and y values both satisfy both equations.

-Multiple solutions: the two lines will intersect each other multiple times, meaning there are multiple set points where the x and y values satisfy both equations. You usually will not have to worry about these problem sets.

-Infinite solutions: the two lines are both the same line, which means every x and y value will satisfy both equations.

Looking at the solution attached, we can see that there are no places where a system of equations intersect, therefore ruling it that they have no solution.

And to answer your last question, an asymptote is a imaginary line in which a equation can approach closely and closely, but will never touch that imaginary line. Think of a line at y=\frac{1}{x}. When you graph it, you can see that the two lines never ever EVER intersect the y-axis, or x=0; giving that x=0 as a vertical asymptote.

5 0
2 years ago
Evaluate 3× +7 for x=5.​
juin [17]

Answer:

The answer is 22!

Step-by-step explanation:

3*5 = 15, 15+7 = 22

Brainliest pls! :D

6 0
3 years ago
Set up and solve the following using dimensional analysis.
Softa [21]
1).  Multiply (5400 inches) by (1 foot / 12 inch) then by (1 mile / 5280 foot).

      (See explanation at the bottom)

         =      (5400 inch) x (1 foot / 12 inch) x (1 mile / 5280 foot)

         =      (5400 x 1 x 1 / 12 x 5280)  (inch - foot - mile / inch - foot) 

         =          0.0852  mile  


2).  Multiply (16 week) by (7 day/week) then by (24 hour/day)
       then by (60 minute/hour) then by (60 sec/minute).

3).  Multiply (54 yards) by (3 foot/yard) then by (1 meter/3.28 foot)
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4).  Multiply (36 cm/second) by (3600 second/hour) then by (1 meter/100 cm)
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5).  Look up how many grams in a pound  ('P')
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6).  Multiply (32 foot/sec) by (1 meter / 3.28 foot) then by (60 sec/minute).


Each time I told you to multiply by something, it was always a fraction
where the numerator and denominator are equal, like (60 seconds/minute)
or (1 foot / 12 inch).  Since the top and bottom of the fraction are equal, the
value of the fraction is ' 1 ' , and multiplying by it doesn't change the value,
it only changes the units ... that's what this whole exercise is about.
When you multiply, KEEP the units in the product, and then, after you multiply, you can 'cancel' units out of the top and bottom of the product.
Like if you have 'feet' on top and bottom, just cross them out.  When you're done, if you did it correctly, the last unit you end up with will be the one you want.      
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3 years ago
Find the sixth term in the following arithmetic sequence.<br> 1/4 , 1/8 ,0...
Shtirlitz [24]

Answer: 3/8

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3 0
3 years ago
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