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Trava [24]
3 years ago
13

PLEASE HELP Do NOT GET HOW TO DO THIS

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

they both have the equilateral lines on each side

Step-by-step explanation:

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Hey, I was wondering, what is 3(6m)+m??? Who can help me???
N76 [4]
<span>What is 3(6m) + m?

3(6m) + m = 
m becomes 1m
9m + 1m =
10m

3(6m) + m is 10m when combining like terms. </span>
6 0
2 years ago
Find the area of the regular pentagon. 4.1 cm 6 cm Area = [?] cm? Enter your answer to the nearest tenth. ​
Assoli18 [71]

Answer:

Area of the given regular pentagon is 61.5 cm².

Step-by-step explanation:

Area of a regular polygon is given by,

Area = \frac{1}{2}aP

Here, a = Apothem of the polygon

P = Perimeter of the polygon

Apothem of the regular pentagon given as 4.1 cm.

Side of the pentagon = 6 cm

Perimeter of the pentagon = 5(6)

                                             = 30 cm

Substituting these values in the formula,

Area = \frac{1}{2}(4.1)(30)

        = 61.5 cm²

Therefore, area of the given regular pentagon is 61.5 cm².

8 0
2 years ago
30 POINTS please help me!
Stels [109]
To prove a similarity of a triangle, we use angles or sides.

In this case we use angles to prove

∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)

∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)

∠BAC = ∠EFD (sum of ∠s in a triangle)

Now we know the similarity in the triangles.

But it is necessary to write the similar triangle according to how the question ask.

The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.

∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED

Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.

Answer is ∆ABC is similar to ∆FED.
7 0
3 years ago
Determine the range of the function.
HACTEHA [7]
Answer is A all real numbers
5 0
3 years ago
What is the measure of an angle whose sine is√3/2 ? 60 45 30
dem82 [27]
ANSWER

The required angle is
60 \degree

EXPLANATION

Let the angle whose sine is
\frac{ \sqrt{3} }{2}
be
x \degree

Then

\sin(x \degree)  =  \frac{ \sqrt{3} }{2}


We take the inverse sign of both sides to obtain,

x =  \sin ^{ - 1} ( \frac{ \sqrt{3} }{2} )

We use our scientific calculator to evaluate and obtain,

x = 60 \degree
8 0
3 years ago
Read 2 more answers
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