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lakkis [162]
3 years ago
10

Which statement best compares a line and a point? (1 point)

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

A point has no dimension and a line has one dimension.

Step-by-step explanation:

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Blank percent of 50 shirts is 35 shirts
kirill [66]

x\% \times 50 = 35 \\  \dfrac{x}{100}  \times 50 = 35 \\ x = 35 \div 50 \times 100 \\ x = 70

Answer check :
50 \times  \dfrac{70}{100}  \\  = 35

Answer : 70%

Hope this helps. - M
4 0
3 years ago
When does the graph of a quadratic function open upward of downward
sveticcg [70]
It opens upward when X is an even power. It would be for X squared or X raised to the 4th power.

6 0
3 years ago
Find the slope of the line that passes trough(5,-10) and (5,-4)
Gwar [14]

Answer:

Answer Undefined

Step-by-step explanation:

This line is a vertical line because the x coordinate is the same on both points (5 is the x coordinate in both points). Vertical line's slopes are undefined because they go from up to down.

3 0
3 years ago
Read 2 more answers
18) Mala gave Kamala half the number of sweets she had. She then had 7 sweets left. How many sweets did Mala have at the start?​
bixtya [17]

Answer:

Mala had 14 sweets at the start.

Step-by-step explanation:

7 x 2 = 14

To check, 14/2 = 7. (Dividing by 2 is the same as multiplying by 1/2)

4 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
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