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zhuklara [117]
3 years ago
13

A 10-year study (lasting from January 1, 2008 to December 31, 2017) was conducted examining the risk of developing lung cancer a

mong a group of 5 participants who were all exposed to asbestos without proper personal protective equipment when working in retrofitting old buildings. On the date the study began, the 5 exposed workers were enrolled and all screened negative for lung cancer. Since cancer can take time to develop, the workers were followed for 10 years and were re-screened at the end of each year (December 31st). The following represents the information the researchers collected from each of the 5 participants.
a. Calculate the prevalence of cancer on January 1, 2017 in the high-risk sample.
b. Calculate the incidence of cancer between January 1, 2017 – January 1, 2018 in the high-risk sample.
c. Calculate the prevalence of cancer on January 1, 2018 in the high-risk sample.

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

Detailed step wise solution is given below:

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If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal
Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that 2x^2+y^2=17

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

4x+2yy'=0

2x+yy'=0

yy'=-2x

y'=-\frac{2x}{y}

Again differentiate w.r.t.x

Then , we get

2+(y')^2+yy''=0 (u\cdot v)'=u'v+v'u)

2+(y')^2+yy''=0

Using value of y'

yy''=-2-(-\frac{2x}{y})^2

y''=-\frac{2+(-\frac{2x}{y})^2}{y}

Substitute x=2 and y=3

Then, we get y''=-\frac{2+(\frac{4}{3})^2}{3}

y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}

Hence,y''=-1.26

6 0
3 years ago
Need a gf then i got you
Novosadov [1.4K]
Hi i’m answering on here so i can ask someone something through the messages bc i haven’t answered enough questions
6 0
3 years ago
Read 2 more answers
Need help on math question thanks <br> A) 0.303 <br> B) 0.435 <br> C) 0.406<br> D) 0.154
Airida [17]

Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

P(\frac{B}{M} ) = 0.3030

Step-by-step explanation:

<u>Explanation</u>:-

Given data

                      Brown           Blue           Hazel           Green

Females           13                  4                  6                   9          

Males                10                  2                 9                   12

<em>Let 'B' be the event of brown eyes </em>

<em>Total number of males n(M) = 33</em>

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>

<em></em>P(\frac{B}{M} ) = \frac{n(B)}{n(M)}<em></em>

<em>From table the brown eyes from males = 10</em>

P(\frac{B}{M} ) = \frac{10}{33}

P(\frac{B}{M} ) = 0.3030

<u>Final answer</u>:-

The probability that a randomly selected student from the class has brown eyes , given they are male

P(\frac{B}{M} ) = 0.3030

8 0
3 years ago
8n + 12 - 5n = 21<br> n=?
insens350 [35]

Answer:

n=3

Step-by-step explanation:

Simplifying

8n + 12 + -5n = 21

Reorder the terms:

12 + 8n + -5n = 21

Combine like terms: 8n + -5n = 3n

12 + 3n = 21

Solving

12 + 3n = 21

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.

12 + -12 + 3n = 21 + -12

Combine like terms: 12 + -12 = 0

0 + 3n = 21 + -12

3n = 21 + -12

Combine like terms: 21 + -12 = 9

3n = 9

Divide each side by '3'.

n = 3

Simplifying

n = 3

5 0
3 years ago
Read 2 more answers
A boat is being pulled into a dock with a rope attached to the boat at water level. When the boat is 12 feet from the dock, the
Natali5045456 [20]

Given :

A boat is being pulled into a dock with a rope attached to the boat at water level. When the boat is 12 feet from the dock, the length of the rope form the boat to the dock is 3 feet longer than twice the height of the dock above the water.

To Find :

The height of the dock.

Solution :

This will make a right angle triangle as given in link below .

Now , applying Pythagoras theorem :

(2h+3)^2=h^2+12^2\\\\4h^2+9h+9=h^2+144\\\\h^2+4h-45=0\\\\(h-5)(h+9)=0

Now , h = 5 or h = -9 .

Now , height cannot be negative .

So , height of the dock is 5 ft .

Hence , this is the required solution .

8 0
3 years ago
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