All categories

3 years ago

Consider the function h(x)= -2cos(8x-(pi/4))+5. What transformation results in j(x)= -2 cos (8x -(pi/4))-5 ?

Mathematics

2 answers:

Ivenika [448]3 years ago

7 0

Answer: B

translating 10 units down

Step-by-step explanation:

Mademuasel [1]3 years ago

4 0

Answer:

B Translating 10 units down

Step-by-step explanation:

The only difference between the two functions is the value of D in the first one it is 5 and in the second it is -5 the difference between the two values is 10 so you would be moving down 10 units.

You might be interested in

Since 300 - 1 does not equal 1 - 300, we say that subtraction does not have the commutative property property of zero associativ

alexira [117]

3n yo _2222224455555

Step-by-step explanation

3 0

2 years ago

What's 100 times 100 {ik it I just wanted to post something} UwU

MariettaO [177]

Answer:

10000

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Mason has lunch at a restaurant and the cost of his meal is $30. Mason

alekssr [168]

Answer:

Step-by-step explanation:

30*20%= 6 so $6.00 tip

Total with tip is $36.00

3 0

3 years ago

Read 2 more answers

Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?

mixer [17]

Given:

$|u|=10$ at an angle of 45°.

$|v|=13$ at an angle of 150°.

$w=u+v$

To find:

Magnitude and direction angle of w.

Solution:

We have,

$w=u+v$

$\theta = 45^\circ, \phi = 150^\circ$

Now,

$u_x=|u|\cos \theta=10\cos 45^\circ=7.071$

$u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071$

$v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833$

$v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5$

Using these information, we get

$R_x=u_x+v_x=7.071-11.25833=-4.18733$

$R_y=u_y+v_y=7.071+6.5=13.571$

$\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})$

$\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})$

$\text{Direction angle}=-72.8239$

$\text{Direction angle}=107.1476$

$\text{Direction angle}\approx 107.1$

Now,

$|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}$

$|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}$

$|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}$

$|w|=14.20236$

$|w|\approx 14.20236$

Therefore, the correct option is D.

4 0

3 years ago

Read 2 more answers

2 1/5 liters of water and 1 1/3 liters of juice are used for a team breakfast,

Dominik [7]

Answer:

3 8/15

Step-by-step explanation:

2 1/5 + 1 1/3 = 3 8/15

6 0

3 years ago