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Anna35 [415]
3 years ago
8

Last year, Cayman Corporation had sales of $7,000,000, total variable costs of $3,000,000, and total fixed costs of $1,500,000.

In addition, they paid $480,000 in interest to bondholders. Cayman has a 35% marginal tax rate. If Cayman's sales increase 7%, what should be the increase in earnings per share?
a. 8.7%
b. 13.9%
c. 11.2%
d. 10.8%
e. 13.3%
Business
1 answer:
UNO [17]3 years ago
3 0

Answer:

b. 13.9%

Explanation:

sales                   7,000,000

variable cost   <u>  (3,000,000)  </u>

contribution       4,000,000

fixed cost           (1,500,000)

interest              <u>   (480,000)  </u>

EBT                     2,020,000

tax expense          (707,000)

net income           1,313,000

contribution margin 4,000,000 / 7,000,000 = 4/7

if sales increase by 7%:

7,000,000 x 0.07 x 4/7 x (1- 0.35) = 182,000

income after increase in sales: 1,313,000 + 182,000 = 1,495,000

increase in earnings: 1,495,000 / 1,313,000 - 1 = 0.138613861 = 13.9%

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hjlf

Answer:

$84,000

Explanation:

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The year 2017 preference share dividend pay out is 5% of 100 multiplied by 12,000 = $60,000

Deduct $ 60,000 from $144,000 dividend declared in 2017 , the balance is common stockholders dividend.

144,000 minus 60,000 = $84,000

Non cumulative preference shares dividend are paid first for the year the company declares dividend. The dividend is not cumulative ( prior years dividend for which company did not declare dividend are forfeited).

The common stockholders are paid dividend after preference shares dividend are paid. The common stockholders bears the full risk of the business as seen above. In event of liquidation, they are the last to be settled from realised asset of the bankrupt company.

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2 years ago
Which are results of regulation in a mixed-market economy? Check all that apply.
solong [7]

<u>Answer:</u> Option 1 and Option 5

<u>Explanation:</u>

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8 0
3 years ago
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Mike and Karen were divorced. Their only marital property was a personal residence with a fair market value of $1.5 million and
Soloha48 [4]

Answer:

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$175,000

Explanation:

a) Data and Calculations:

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Cost of property =  $575,000

Residual value =     $925,000

Alimony to Karen = $750,000 ($150,000 * 5)

Balance (Mike's) =  $175,000

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6 0
1 year ago
The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

3 0
3 years ago
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