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Brums [2.3K]
3 years ago
5

This is the graph of y = sin(x). Does anyone know the second part?

Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer:

The resulting graph is y = 5\cdot \sin x.

Step-by-step explanation:

The resulting function is of the form:

y = A\cdot \sin x + k

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

A - Amplitude, dimensionless.

k - Midpoint value, dimensionless.

The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: A > 0. According to the graph, the function is bounded between 5 (y_{max}) and -5 (y_{min}), and the midpoint value (k) is 0. The amplitude is determined by the following calculation:

A = \frac{y_{max}-y_{min}}{2}

If y_{min} = -5 and y_{max} = 5, then:

A = 5

The resulting graph is y = 5\cdot \sin x.

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Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals45 and x overbar
Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : n=45

\overline{x}=148.79\text{ lb}

\sigma=31.37\text{ lb}

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = \mu=148.79\text{ lb}

b) The confidence interval for the population mean is given by :-

\mu\ \pm E, where E is the margin of error.

Formula for Margin of error :-

z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha=1-0.90=0.1

Critical value : z_{\alpha/2}=z_{0.05}=\pm1.645

Margin of error : E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69

Now, the 90% confidence interval for the population mean will be :-

148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)

Hence, the 90​% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0
3 years ago
Paula spent 3/8 of her allowance on clothes and 1/6 on entertainment what fraction of her allowance did she spend on other items
Alexandra [31]
3/8=9/24 and 1/6=4/24
9/24+4/24=13/24
Paula spent 13/24 of her allowance on other items.
8 0
3 years ago
Read 2 more answers
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
3 years ago
Ten frequent gamers are randomly selected. The random variable represents the number of frequent gamers who play video games on
notsponge [240]

Answer:

For this to be a binomial experiment, the assumption that is made is:

C. The probability of being selected is the same for all ten gamers.

Step-by-step explanation:

a) A binomial experiment must meet the following four conditions:

1. The experiment must consist of 'n' identical trials.

2. Each experiment must result in one of the two outcomes of either success or failure.

3. The probability of success (p) must remain the same from one experiment to the next.

5 0
2 years ago
Read 2 more answers
Can someone please help me with this question please please help me I really really need help please.
harina [27]

Answer:

1st : neither linear nor nonlinear

2nd: nonlinear

3rd: linear

4th: both linear and nonlinear

4 0
3 years ago
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