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3 years ago

The following graph shows a seventh-degree polynomial

Mathematics

1 answer:

Leno4ka [110]3 years ago

3 0

Answer:

Step-by-step explanation:

Basically you can see it hits -5 as a minimum and that means there is 2 there and then -1 and then hits 4 3 times and then 7

So your answer is x=-5 with multiplicity of 2 x=-1 and x=4 with multiplicity of 3 and x=7 once.

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Find the volume of the square pyramid and round to the

Brrunno [24]

The answer is to multiply

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3 years ago

The total area of two square windows is 1,025 in.^2. each side of the larger window is 5 in. longer than the sides of the smalle

vampirchik [111]

The area of a square is expressed as:

Area = s^2

We are given the area of both windows. We will use this value for the calculations. We set s as the side of the larger window and a for the smaller window.

Total area = Area larger + area smaller
1025 = s^2 + a^2

Since it was said that the side of the larger window, s is 5 in longer than the side of the smaller window, a (s = 5+a) then:

<span>1025 = s^2 + a^2
</span>1025 = (5+a)^2 + a^2

simplifying we obtain,

a = 20 inches

8 0

3 years ago

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You have a garden in your backyard that measures 15 meters by 20 meters. You want to place stepping stones around the perimeter

Anettt [7]

Answer:

0.5 m

Step-by-step explanation:

Given that the dimensions of the garden are 15 meters by 20 meters.

The area of the new garden (original garden + stone placed around the perimeter) is 336m².

Let d be the width of the border having stepping stones as shown in the figure. The shaded region in the figure is the area having stepping stones.

The area including the shaded region $= (15+2d)(20+2d) m^2$

$\Rightarrow 336 = (15+2d)(20+2d) \\\\\Rightarrow 336 = 300+ 70 d +4d^2 \\\\\Rightarrow 4d^2 +70d+300-336=0 \\\\\Rightarrow 4d^2 +70d-36=0 \\\\\Rightarrow 2d^2 +35d-18=0 \\\\\Rightarrow 2d^2 +36d-d-18=0 \\\\\Rightarrow (2d-1)(d+18)=0 \\\\\Rightarrow (2d-1)=0, \; or \; (d+18) \\\\\Rightarrow d= 0.5\;or -18 \\\\$

As the width of the stone border can't be a negative value, so taking the positive value.

Hence, the width of the stone border is 0.5 m.

So, the wi

7 0

3 years ago

Three high school participated in a study to evaluate the effectiveness of a new computer-based mathematics curriculum. Four 24-

snow_tiger [21]

Answer:

A) experimental

B) The important factors are : Type of instruction, scores and High schools,

The factor levels are :

Level -1 which comprises of 3 highschool,

Level -2 which comprises of highschool and the highschool has 4 sections and each section has 24 students

Factor level combinations:

Level 1 : computer and standard based combination

C) Within the subject : 24 students

Between subject : High school

D) score of the test

E) student

Step-by-step explanation:

A) The study is experimental because of the random assignment of two different types of instruction to the students which will control/affect the technique of teaching without just observing the performance of the students from the side

B) The important factors are : Type of instruction, scores and High schools,

The factor levels are :

Level -1 which comprises of 3 highschool,

Level -2 which comprises of highschool and the highschool has 4 sections and each section has 24 students

Factor level combinations:

Level 1 : computer and standard based combination

C) Within the subject : 24 students

Between subject : High school

D) The dependent measure is the score of the test

E) The basic experiment unit of the study is : student

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3 years ago

HELPPPPPPPPPPPPPPPPPPP

FrozenT [24]

Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.

Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of $x \geq 3$ . Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.

All of the other graphs have at least one point in common.
(B) has $x \leq -1$
(C) has $x = 1$
(D) has $x \leq -2$

7 0

3 years ago

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