x = 3 + y Eqn(1)
y = -2x + 9 Eqn(2)
Let us solve the system of equations with the substitution method
x - 3 = y (Subtracting 3 from both sides of the Eqn(1))
Replacing y = x - 3 in Eqn (2), we have:
x - 3 = -2x + 9
x = -2x + 9 + 3 (Adding 3 to both sides of the equation)
x + 2x = 9 + 3 (Adding 2x to both sides of the equation)
3x = 12 ( Adding like terms)
x = 12/3 (Dividing by 3 on both sides of the equation)
x = 4
Replacing x=4 in Eqn(1), we have:
4 = 3 + y
4 - 3 = y (Subtracting 3 from both sides of the equation)
y=1
The answers are:
x= 4 and y=1
The shaded part is AXY, so if you cut the rectangle into smaller parts you will see that AXY takes up 1/8 of the ABCD
Answer:
Tom will need 
gallons of fruit drink.
Step-by-step explanation:
Hint- This question can be solved by unitary method.
Tom has a recipe for punch that calls for 
gallon of fruit drink.
i.e for 1 batch of the punch Tom needs gallon of fruit drink.
For 
batch of the punch Tom needs 
gallons of fruit drink.
Therefore, Tom will need gallons of fruit drink.
Answer: Hello daema, let's let x be the goal and c be the collection per day.
x - 45 + c = x + 5 is the answer so now let's talk about how we did that.
So she wants to get to x which is the goal. But right now she has 45 less than what her goal is. So that would look like this x - 45 now she has to get c or the collection per day to get to her goal. So now it looks like this x - 45 + c. Now that c has to be at least x which is her goal, it now will look like this x - 45 + c = x. But we're not done, the question said that now she 5$ over her goal, or x. So we have to add the + 5 onto the end so now it looks like this x - 45 + c = x + 5. To solve the equation "if you have to" it would be x = 50$ per day.
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
