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Tems11 [23]
3 years ago
8

2. A magazine reports that the average bowling score for league bowlers in the United States is 157 with a standard deviation of

12, and that the scores are approximately normally distributed. State the shape, the mean, and the standard deviation of the mean x of 15 bowlers selected at random. Justify each statement by showing your work or identifying the theorem that tells you your answer is correct.
Mathematics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

The shape is going to be bell-shaped(normally distributed), with mean of 157 and standard deviation of \frac{\sigma}{\sqrt{n}} = \frac{12}{\sqrt{15}} = 3.1

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

So, in this problem:

The shape is going to be bell-shaped(normally distributed), with mean of 157 and standard deviation of \frac{\sigma}{\sqrt{n}} = \frac{12}{\sqrt{15}} = 3.1

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