This is a more difficult one to explain. Let's start with the line to the right. It has a slope (m) of 
= -1 and a y-intercept of +3 (continue the line to see where it crosses the y-axis). So, the equation of that line is: y = -x + 3 when x ≥ 2. This can also be written as y = 3 - x when x ≥ 2. The only option that has that equation is A.
Answer: A
You need to solve this "system of linear equations." In other words, find a point (x,y) that satisfies both 4x-3y=17 and 2x-5y=-11.
Try solution by elimination. Multiply the 2nd equation by -2 to obtain -4x+5y=22. Add this result to the 1st equation. I'd suggest you write this out to see what is happening.
4x-3y=17
-4x+10y=22
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7y=39. Solving for y, we get y=39/7 (a rather awkward fraction).
Now find x. To do this, substitute 39/7 for y in either of the given equations. Solve the resulting equation for x.
Write your solution in the form (x, y): ( ? , 39/7).
Answer:
the answer is G(x)=x^2 + 1
- if you add +1, the y value will increase 1 point upward making the other function equal to g(x)=x^2 + 1. the difference between the two functions is the + 1.
You would take 3 x 4 which equals 12. And then you would take 12 x8 which would equal 96
Answer:
D
Step-by-step explanation:
