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3 years ago

6

Which of these are unit ratesA square yard for every 100 grass seeds4 acres for 800 plants2 plants in a square foot6 plants in 1

square yard8 seeds per square foot25 trees per 25 square yards?

1 answer:

tiny-mole [99]3 years ago

8 0

2 plants in a square foot

6 plants in a square yard

8 seeds per square foot

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Write the absolute value inequality in the form |x-b| c that has the solution set x<-5 or x>7.

Daniel [21]

Answer:
|x - 1| > 6
Step-by-step explanation:
b is the centre:
(-5 + 7)/2
2/2 = 1
b = 1
c is the distance from the centre
c = 7 - 1 = 6
Since it's an or case, > with the modulus
|x - 1| > 6

4 0

3 years ago

I need these so i don't fail.

Nadusha1986 [10]

Answer:

1) (2,2)

2) (2,-1)

3) (-4,1)

Step-by-step explanation:

5 0

3 years ago

Julio says,"If you subtract 15 from my number and multiply the difference by -7,the result is -175." What is Julios number

maw [93]

Answer: 40

Step-by-step explanation:

Assume Julio's number is x.

The expression would be:

-7 * (x - 15) = -175

x - 15 = -175/-7

x = -175/-7 + 15

x = 40

7 0

3 years ago

Jasmine has taken an online boating safety course and is now completing her end of the course exam. As she answers each question

anzhelika [568]

Answer:

80 questions.

Step-by-step explanation:

If 20% = 16 Q,

then 100 ÷ 20 = 5

Therefore, 5 x 16 = 80 questions on the test.

8 0

3 years ago

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

6 0

3 years ago