Assuming that the equations are (x+7) and (3x-8) because the first equation does not have a sign these are the steps. When you multiply you will get 3x^2+21x-8x-56. After this you will simplify and you will get your final answer which is 3x^2+13x-56. Also if I used the wrong equations please let me know and I can help you with the correct ones.
9. The curve passes through the point (-1, -3), which means

Compute the derivative.

At the given point, the gradient is -7 so that

Eliminating
, we find

Solve for
.

10. Compute the derivative.

Solve for
when the gradient is 2.




Evaluate
at each of these.


11. a. Solve for
where both curves meet.





Evaluate
at each of these.



11. b. Compute the derivative for the curve.

Evaluate the derivative at the
-coordinates of A, B, and C.



12. a. Compute the derivative.

12. b. By completing the square, we have

so that

13. a. Compute the derivative.

13. b. Complete the square.

Then

Answer:
300
Step-by-step explanation:
20÷2=10
60÷2=30
30x10=300
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
2*2+1=5
All you need to do is just use f(g(2)) plug in to the first equation.<span />