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4 years ago

What is the inverse of the function h(x) =3/2(x-11)

Mathematics

2 answers:

Law Incorporation [45]4 years ago

7 0

Answer:

$h^{-1}$ (x) = $\frac{2}{3}$ x + 11

Step-by-step explanation:

let y = h(x) and rearrange making x the subject , that is

y = $\frac{3}{2}$ (x - 11 ) ← multiply both sides by 2 to clear the fraction

2y = 3(x - 11) ← distribute

2y = 3x - 33 ( add 33 to both sides )

2y + 33 = 3x ( divide all terms by 3 )

$\frac{2}{3}$ y + 11 = x

Change y back into terms of x with x = $h^{-1}$ (x) , thus

$h^{-1}$ (x) = $\frac{2}{3}$ x + 11

Fantom [35]4 years ago

5 0

Answer:

Step-by-step explanation:

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