1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fomenos
3 years ago
7

Help plzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:99°

Step-by-step explanation:

180-123=57

x=57+42

x=99°

natali 33 [55]3 years ago
6 0

Answer:

Step-by-step explanation:

You might be interested in
-12/5+3/10/11/14-(-9/14)
jok3333 [9.3K]

Answer:

-6/5

Step-by-step explanation:

I hope it helps, bye

7 0
3 years ago
Replace ∗ with a monomial so that the expression can be rewritten as a square of a sum or a difference: 25a^2+ ∗ + 1/4 b^2
zavuch27 [327]

Answer:

be rewritten as a square of a sum

Step-by-step explanation:

4 0
3 years ago
A triangular prism is 19 centimeters long. It has a triangular face with a height of 14 centimeters. The volume of the prism is
andreyandreev [35.5K]

The base of its triangular face of the triangular prism is found as 17.7 cm.

<h3>What is defined as the triangular prism?</h3>
  • A polyhedron with two triangular bases as well as three rectangular sides is known as a triangular prism.
  • It is a three-dimensional shape with three side faces but also two base faces that are connected by the edges.

The formula for the volume of triangular prism is;

Volume = base area x length

The base area of the triangular base.

The area of the triangle = 1/2 base×height

The given values are-

  • volume = 2,354. 1 cubic centimeters.
  • length = 19 cm
  • height = 14 cm.

Thus, volume = base area x length

volume =  1/2 base × height × length

base = 2v/(height × length)

Put the values;

base = 2×2,354.1/(14 × 19)

base = 4708.2/(14 × 19)

base = 17.7 cm

Thus, the base of the triangular  prism is found as 17.7 cm.

To know more about the triangular prism, here

brainly.com/question/16128664

#SPJ9

7 0
1 year ago
A​ town’s January high temperatures average 36 degrees​ (F) with a standard deviation of 10 degrees while in July the mean high
n200080 [17]

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

January:

z_{score} = \displaystyle\frac{55-36}{10} = 1.9

July:

z_{score} = \displaystyle\frac{55-74}{8} = -2.375

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

3 0
3 years ago
(5 1/4)÷(−2 1/2) <br><br> i need it to be mixed number, in simplified form quick 5 mins plzzz
SOVA2 [1]
First turn then into a decimal, it will be easier to divide. Then, divide the decimal. Take your answer and turn it into a fraction. If it's improper, turn it into a mixed number and simply it, if you have any questions ask
8 0
3 years ago
Other questions:
  • How many dimensions does a plane have?<br><br> A. TWO<br> B. Zero<br> c. Three<br> D.One
    12·1 answer
  • What s the domain of f(x)=3x-2
    13·2 answers
  • Find a pattern for the sum of 4 times a number and twice the sum of the same number and 3
    12·1 answer
  • How to find the first quartile
    12·2 answers
  • Evaluate the expression. 4(x+8)for x =6
    8·1 answer
  • Geometry proof can anyone help
    15·1 answer
  • What is <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Csqrt%7B36%7D%20" id="TexFormula1" title=" - \sqrt{36} " alt=" - \sq
    12·1 answer
  • ( Which word from List 1 BEST completes this analogy?
    15·1 answer
  • What is the area of a triangle with 13 x 13 x 10?
    11·1 answer
  • Compute the following 5/9+1/4
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!