The diameter of the outer ring will be 4 inches since it extends one inch beyond the bull's eye from either side. See the attached image for clarification.
The area of the outer ring can be expressed as:

This is because we need to take into account of the space taken up by the bullseye.
Now we set up our equation:

Now plug and solve:


Answer:
Step-by-step explanation:
Answer:
- amplitude: 3
- period: π
- axis: y = 0
- range: [-3, +3]
Step-by-step explanation:
The amplitude is the multiplier of the sine function: 3.
The period is 2π divided by the coefficient of x: 2π/2 = π.
The equation of the axis is any added constant: y = 0.
The range is the axis value ± the amplitude value: from -3 to +3.
Please be specific about your question (write full information so that i can understand what is all about)
Answer:
190
Step-by-step explanation:
10x5x2=100
5x3x2=30
3x10x2=60
100+30+60=190