PLEASE HELP

I'm totally lost on this one. How do you do this problem? (Only #11)

dedylja [7]

Answer is A. Hope this helped

4 0

4 years ago

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Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)

muminat

Answer:

The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = $\frac{-5}{2}$ x + $\frac{12}{2}$

Or, y = $\frac{-5}{2}$ x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = $\frac{-5}{2}$

Again,

The other line if passing through the points (- 2 , 3 ) And is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So, M = m = $\frac{-5}{2}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = $\frac{-5}{2}$ × ( - 2 ) + c

or, 3 = $\frac{10}{2}$ + c

Or, 3 = 5 + c

∴ c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope $\frac{-5}{2}$ and passing through points ( -2 , 3)

y = $\frac{-5}{2}$ x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And is perpendicular to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So, M' × m = - 1

Or, M' × $\frac{-5}{2}$ = - 1

Or, M' = $\frac{-1}{\frac{-5}{2}}$

Or, M' = $\frac{2}{5}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = $\frac{2}{5}$ × ( - 2 ) + c'

or, 3 = $\frac{- 4}{5}$ + c'

Or, 3 × 5 = - 4 + 5× c'

∴ 5 c' = 15 + 4

or, 5 c' = 19

Or, c' = $\frac{19}{5}$

So, The equation of line with slope $\frac{2}{5}$ and passing through points ( -2 , 3)

y = $\frac{2}{5}$ x + $\frac{19}{5}$

y = $\frac{2 x + 19}{5}$

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0

3 years ago

With a principal investment of $19,200, which account will have the greatest value after 5 years? simple interest: I = P • r • t

grin007 [14]

Given:
Principal: 19,200
term: 5 years

a) Interest compounded annually:
A = 19,200 (1 + 0.036)^5
A = 19,200 (1.036)^5
A = 19,200 (1.1934)
A = 22,913.28

b) Simple Interest
I = 19,200 * 0.038 * 5
I = 3,648.38

19,200 + 3,648.38 = 22,848.38

c) Interest compounded annually
A = 19,200 (1 + 0.034)^5
A = 19,200 (1.034)^5
A = 19,200 (1.182)
A = 22,694.40

d) Interest compounded quarterly
A = 19,200 (1 + 0.032/4)^4*5
A = 19,200 (1 + 0.008)^20
A = 19,200 (1.008)^20
A = 19,200 (1.173)
A = 22,521.60

8 0

4 years ago

8x-11+5x+2x+6=180 what is the measurement for x.

Verizon [17]

I assume you're looking for the value of x?

Combine like terms: 8x+5x+2x-11+6=180 -> 15x-5=180

Add 5 to both sides: 15x=185

Divide both sides by 15: x=12 1/3

So x is 12 1/3 or 37/3

Hope this helped!

6 0

3 years ago

The rule below shows how Mrs. Murphy's long-distance phone company computes her monthly bill. Which answer expresses that rule i

Phoenix [80]

The answer is 29.04 hope its rite

5 0

4 years ago

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