3 years ago

Answer the following for each letter true or false.

1 answer:

6 0

A. False
B. True
C. False
D. True

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Ne4ueva [31]

$f(x)=\dfrac{x}{2}-3,\ g(x)=3x^2+x-6\\\\(f+g)(x)=f(x)+g(x)=\left(\dfrac{x}{2}-3\right)+(3x^2+x-6)=\dfrac{1}{2}x-3+3x^2+x-6\\\\=3x^2+1\dfrac{1}{2}x-9$

$Answer:\ \boxed{B.\ 3x^2+\dfrac{3}{2}x-9}}$

8 0

3 years ago

Alenkasestr [34]

4 to the second power. Just find the squared root of 16

7 0

3 years ago

aev [14]

Answer:

answer below:)

Step-by-step explanation:

Basically, start off by simplifying each pair of numbers.

The first one: $2^{2}$ x 5 = 4 x 5 = 20

The second one: $11^{1}$ = 11

The third: $8^{2}$ -60 = 64 - 60 = 4

Now from least to greatest, so that would be 4, 11, 20 or in this case it would then be $8^{2}$ -60, $11^{1}$ , $2^{2}$ x 5

Hope it helped, good luck!!

5 0

3 years ago

ahrayia [7]

Answer:

I need a question for an answer.

Step-by-step explanation:

.....

7 0

3 years ago

kirill115 [55]

Plug in -3 for x and you will get 37

7 0

3 years ago