Find the product of 18 and 287. 0 4,066 2,583 5,166 O 4,516

• Since January 1980, the population, P, of the city of Brownville has increased closely modeling the

igomit [66]

Answer:

B) The population is increasing by 102.2% each year.

A) 720,500 represents the initial amount of people in January 1980 and 1.022 represents the increase factor that multiplies to the amount.

Step-by-step explanation:

1.022 times 100 equals 102.2% (a number in the decimals place times 100 give you the percent).

6 0

3 years ago

WILL GIVE THE BRAINLIEST FOR A CORRECT AND A NON GUESSED JUST FOR POINTS QUESTION Victor wants to conduct a survey to find how m

givi [52]

D would be more logic because the total of kids playing football and hour everyday and he would be able to count for in a whole week

3 0

3 years ago

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Factorise fully 72-2y^2

KiRa [710]

Answer: 2(y + 6)(-y + 6)

Step-by-step explanation: Factor 72 - 2y^2

-2y^2 + 72

= 2(y + 6)(-y + 6)

7 0

3 years ago

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X^2+4x+20=12x-5 Solve this equation

Scrat [10]

Answer:

4 + (or -) 3i

Step-by-step explanation:

Hi!

Alright, so we're going to move all of the variables and constants to one side. Then, using the quadratic formula, we'll find the answer.

1. Move 12x-5 to the left side of the equation by

a. Subtracting 12x from both sides

b. adding 5 to both sides.

1: x^2+4x+20-12x+5

2. Group the common terms

x^2+4x-12x+20+5 --> x^2-8x+25

3. Look at the problem. We can't factor this.

Explanation for why this isn't factorable (you can skip this)

(1) 25 is positive, so its two factors will both be either positive or negative. We're looking for a negative 8, so let's go with negative.

(2) Factors of 25: 1 & 25, 5 &5

Seeing the problem? Ya, none of the factors of 25 sum to eight. So, instead, we're going to use the quadratic formula.

4. So, the quadratic formula: $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Our equation is x^2-8x+25=0

a is the constant in front of the x^2

b is the constant in front of the x

c is the term without any x values

so, a=1, b=-8, and c= 25

Into equation:

$\frac{8+-\sqrt{64-4(1)(25)} }{2a}$ = $\frac{8+-\sqrt{64-100} }{2}$ = $\frac{8+-\sqrt{-36} }{2}$

8/2 = 4

sqrt(-36) = 6i

6i/2 = 3i (remember, we still have the two in the denominator)

4 + (or -) 3i

8 0

2 years ago

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

2 years ago