C and D.............................
No they are not equivalent
Y=mx+b or -2=-1 x 2+b, b= -2(-1)(2) b=0
Therefore the equation of the line is
y=-1x
Answer:
(2,-17) should be the minimum.
Step-by-step explanation:
The minimum of a quadratic function occurs at 
. If a is positive, the minimum value of the function is 
occurs at
Find the value of
x = 2
evaluate f(2).
replace the variable x with 2 in the expression.
simplify the result.
The final answer is -17
Use the x and y values to find where the minimum occurs.
HOPE THIS HELPS!
Answer: a) -13/16
Step-by-step explanation: Start by setting equations equal and rearrange X^3 - x^2 + 1 = 0. Visual inspection of graph shows x between -1 and -1/2. Start with x = 3/4 plug in and calculate: just a little too small. Try going halfway towards -1: x =-7/8 Plug in and the answer is very far from 0. Go halfway back towards -3/4: -13/16 and the equality is very close.
