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Ivan
3 years ago
9

What is the value of z for the equation fraction 1 over 3z = −fraction 5 over 6 + fraction 1 over 6z? 5 2 −2 −5

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0
We will multiply both sides of an equation by  6 z :

\frac{1}{3z}=- \frac{5}{6}+ \frac{1}{6z} /*6z
\frac{6z}{3z}=- \frac{30z}{6}+ \frac{6z}{6z}
2=-5z+1
2-1=-5z
1=-5z
z=- \frac{1}{5}
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The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
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Paul's collection:

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IQR = 6

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Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

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absolute deviation from mean is:

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:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

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1930

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first quartile becomes

1902+1908)/2

Q1=1905

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1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

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Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

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absolute deviation from mean is:

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We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

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