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uranmaximum [27]
4 years ago
12

Can anyone help??????

Mathematics
2 answers:
ella [17]4 years ago
7 0

Answer:

The answer is C or 109.5 units

Step-by-step explanation:

We have to use the trig function cosine to find the answer.

cosine = \frac{adjacent}{hypotenuse}

cosine of 64 = 0.438371147

the equation is:      cos 64 = \frac{48}{hypotenuse}

So using this equation,

we must divide 48 by the cosine of 64 to get the hypotenuse

this equals 109.5

The hypotenuse is our length that we need to find so the question is solved.

Hope This helps

Branliest is appreciated!

sineoko [7]4 years ago
6 0

Answer:

C) 109.5

Step-by-step explanation:

Use cosine of 64°

cos 64° = 48/x

Put x on one side

x = 48/ cos 64°

x = 109.4962576

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Blababa [14]

Answer:

|A| = - 28

Step-by-step explanation:

Given

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

Required

Determine the determinant

For a two by two matrix, A such that:

A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant |A| is:

|A| = a * d - b * c

So, in

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

The determinant is:

|A| = -2 * 5 - 6 * 3

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6 0
3 years ago
Here is a riddle:
lilavasa [31]

Answer:

The system of inequalities that represents this situation will be:

f + s < 10

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Step-by-step explanation:

  • Let 'f' represent the first number
  • Let 's' represent the second number.

Given that the sum of the two numbers is less than 10. As 'less than' can be represented by '<'.

  • so the inequality would be: f + s < 10

Given that If we subtract the second number from the first, the difference is greater than 3. As 'greater than' can be represented by '>'.

  • so the inequality would be: f-s > 3

Thus, the system of inequalities that represents this situation will be:

f + s < 10

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8 0
3 years ago
Given: Parallelogram ABCD,
andreyandreev [35.5K]

Answer:

a. m DCB =<DAB=120 opposite angle of the parallelogram are equal

again

BP=PD diagonal bisect it

3x+7=-x+17

3x+x=17-7

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4 0
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Kirk used 10.2 centimeters of tape to wrap 3 presents. How many presents did Kirk wrap if he used 23.8 centimeters of tape?
insens350 [35]

Answer:

Kirk wrapped 7 presents with those 23.8 cm of tape.

Step-by-step explanation:

Figure out the unit rate:

10.2 cm tape

-------------------

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or

   3 presents

-----------------------

  10.2 cm tape

Multiplying this by 23.8 cm results in the number of presents Kirk wrapped with that much tape:

(3 presents)(23.8 cm tape

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Kirk wrapped 7 presents with those 23.8 cm of tape.

7 0
3 years ago
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