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sleet_krkn [62]
3 years ago
5

A point has coordinates A(-2, 4). Find the coordinates of its image if it's translated by (x - 2, y - 1). A'(0, 5) A'(0, 3) A'(-

4, 3) A'(-4, 5)
Mathematics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

A'(-4, 3)

Step-by-step explanation:

The given point is A(-2,4).

If this point is translated by the rule:

(x,y)\to (x-2,y-1), then we can obtain the image of A(-2,4) by plugging x=-2 an y=4 into the rule.

\implies A(-2,4)\to A'(-2-2,4-1)

\implies A(-2,4)\to A'(-4,3)

The correct choice is  A'(-4, 3)

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anyanavicka [17]

a. x^4 + 4x^2 + 4

b. x = ∛-1 and -3

<h3>How to expand the expression</h3>

a.  Given

(x² + 2)²

First, we open up the bracket

(x^2 + 2) (x^2 + 2)

Multiply through

x^4 + 2x^2 + 2x^2 + 4

Collect like terms

x^4 + 4x^2 + 4

b. Let's factorize

x^4 + 4x + 3

Find the factors of 3 that are products of 4, they are 3 and 1

Use it to replace 4x as 3x and x

x^4 + 3x + x + 3

Let's make the expression two

(x^4 + 3x) (x+ 3)

Find the common factor

x^3(x + 3)+ 1(x+ 3)

So,

x^3 + 1 = 0 and x + 3 = 0

x = 3\sqrt{-1} and x = -3

Thus, x = ∛-1 and -3

Learn more about factorization here:

brainly.com/question/25829061

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4 0
2 years ago
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lora16 [44]

Answer:

1/5

Step-by-step explanation:

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4 0
2 years ago
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Answer:

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Step-by-step explanation:

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