Answer:
Step-by-step explanation:
This is a special die. Its six sides bear the numbers {9, 10, 11, 12, 13, 14}.
There are three possibilities for getting a multiple of two: {10, 12, 14}, and
there is only one possibilities for getting a multiple of ten: {10, 12, 14}
The probability here of getting a multiple of two is 3/6, and that of getting a multiple of ten is 1/6. But one of the outcomes is found in both result sets: 10. Getting a multiple of 10 is already included in the event that the outcome is a multiple of two. My answer here would be 3/6, or 1/2.
B = 2A/h
The way you would get this is first by clearing the fraction. So in order to clear the fraction, you have to multiply the equation by the denominator.
2(A = 1/2bh)
2A = 1bh
2A = bh
Then you have to isolate the variable. So you'd divide bh by h in order to get b by itself. So you'd end up with:
2A/h = bh/h
2A/h = b
If TU is 7.5 and UC is 17.5, TV = 25 because you just add the two together
32a+30=YOU,
58b+44=YOU, a,b and YOU are integers; YOU<3000.
YOU can be 798, 1726, or 2654.
X+8 because ur adding 8 to a number (x)
