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Tpy6a [65]
3 years ago
6

Classify each function as a power function, root function, polynomial (state its degree), rational function, algebraic function,

trigonometric function, exponential function, or logarithmic function:f(x) = log2X b(x) = 4 sqrt(X) h(x) = 2x3 / 1-x2 u(t) = 1 – 1.1t + 2.54t2 v(t) = 5t w(theta) = sin(theta) cos2(theta)
Mathematics
1 answer:
koban [17]3 years ago
6 0
Classify by functions
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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
PLZ HELP INSCRIBED ANGLES
den301095 [7]
54
 because when you do 

7 0
3 years ago
The points in the table lie on a line. Find the slope of the line.
wolverine [178]
Answer

Y=5x+2

I’m not sure but I think that’s the answer
8 0
3 years ago
A restaurant did a survey among 100 customers to find their food preferences. The customers were asked about their preferences f
bixtya [17]

The values for the first part is..25 like choc...25 do not like choc..25 for the 3rd and yes..25 for 4th

Part b...zero percent..every 1 liked on or the other

Part c..it's equal for like choc..and same like cheese..

6 0
3 years ago
The sums of two prime numbers is 85.what is the product of these two numbers
vladimir1956 [14]
So prime numbers are numbers which cant be divided by any number other than one and these are <span>2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, </span>61<span>, </span>67<span>, </span>71,73<span>, </span>79<span>, </span><span>83

83+2 is 85
so the product is the two numbers multiplied together which is 166</span>
4 0
3 years ago
Read 2 more answers
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