Question

Solve for x...............

Answer 1

Answer:

Option A

$x=\frac{2(+/-)\sqrt{10}} {2}$

Step-by-step explanation:

we have

$2x^{2}-4x-3=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}-4x-3=0$

so

$a=2\\b=-4\\c=-3$

substitute

$x=\frac{4(+/-)\sqrt{-4^{2}-4(2)(-3)}} {2(2)}$

$x=\frac{4(+/-)\sqrt{40}} {4}$

$x=\frac{4(+/-)2\sqrt{10}} {4}$

$x=\frac{2(+/-)\sqrt{10}} {2}$

Answer 2

Answer:

Choice A is correct answer.

Step-by-step explanation:

Given equation is :

2x²-4x-3=0

ax²+bx+c= 0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to find the value of x.

Comparing general quadratic equation with given quadratic equation,we get

a = 2, b= -4 and c = -3

Putting above values in quadratic equation,we get

x = (-(-4±√(-4)²-4(2)(-3)) / 2(2)

x = (4±√16+24) / 4

x = (4±√40) / 4

x = (4±√10×4) / 4

x = (4±2√10) / 4

x = 2(2±√10) / 4

x = (2±√10) / 2

Hence, solution of 2x²-4x-3= 0 is (2±√10) / 2.